For each of the following scenarios, is the total work done on the object positive, negative, or zero? Question 5 options: A cannonball is fired from a cannon. A box is pushed at a constant speed along a surface with kinetic friction. A box slows down as it's pushed up a ramp. A ball is dropped vertically. A ball is thrown upwards from some height and caught on the way down at the same height. A skydiver jumps from a moving plane and lands safely on the ground. 1.Positive2.Negative3.Zero

Name: For each of the following scenarios, is the total work done on the obj
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Description: For each of the following scenarios, is the total work done on the object positive, negative, or zero? Question 5 options: A cannonball is fired from a cannon. A box is pushed at a constant speed along a surface with kinetic friction. A box slows dow

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Answered: For each of the following scenarios, is…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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For each of the following scenarios, is the total work done on the object positive, negative, or zero?

Question 5 options:

	A cannonball is fired from a cannon.
	A box is pushed at a constant speed along a surface with kinetic friction.
	A box slows down as it's pushed up a ramp.
	A ball is dropped vertically.
	A ball is thrown upwards from some height and caught on the way down at the same height.
	A skydiver jumps from a moving plane and lands safely on the ground.

1.	Positive
2.	Negative
3.	Zero

Expert Solution

Step 1: Concept:

$text We know,Total work done is given as change in the kinetic energy: end text W equals 1 half m v squared subscript f i n a l end subscript minus 1 half m v squared subscript i n i t i a l end subscript space space space space equals 1 half m open parentheses v squared subscript f i n a l end subscript minus v squared subscript i n i t i a l end subscript close parentheses text We can clearly say if : end text v subscript f i n a l end subscript greater than v subscript i n i t i a l space space end subscript space space space space W space i s space plus v e v subscript f i n a l end subscript less than v subscript i n i t i a l space space end subscript space space space space W space i s space minus v e v subscript f i n a l end subscript equals v subscript i n i t i a l space space end subscript space space space space W space i s space z e r o$

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