For each of the following pairs of complexes, which is least likely to undergo b-hydride elimination?Choose only one from each pair.MLALMTACSelect one:a.MeMeO b.O C.O d.orPh3PосMLMeorPh3POCIdentify complexes A and B and processes 1 and 2:H3C-CH31AHCIBAPh3PCIOCALMA HIKICCOPPh3CIPh3P Ir-PPh3OCPPh3DCOPPh3Ph3POCH.. EtPh3POCPhaPrOCPhaBOCPPh 3BHCIPhaPrOCBPi...BHLMPrCIPriCIPPh3HPPh3MCIPPh3EPPh3-M-GPrPrPr2ororLM1LigandSubstitutionOxidativeAdditionFOxidativeAdditionB1LigandSubstitutionHTime left 103:15:10ReductiveEliminationB-HydrideElimination2ReductiveElimination2B-HydrideElimination For the reaction of the sodium enolate with chlorotrimethylsilane shown below, what is thethermodynamic driving force for this reaction?+ CISiMe3Me Si-ONaO+ NaClSelect one:A. The formation of strong covalent bonds between Sodium and Chloride ions.B. The breaking of weak Na-O and Si-Cl bonds.C. Silicon-oxygen silicon bonds are stronger than silicon-carbon single bonds.D. The formation of the NaCl lattice and release of the lattice enthalpy, coupled with theformation of a strong Si-O bond.For organolithium clusters of the general formula (RLi)6, reaction with additional Lewis basicdonor ligands leads to deaggregation and formation of smaller rings than the 6 memberedrings seen in the original cluster. For internally solvated clusters, however, 6 membered ringsare possible. Why?Select one:O A. Internal solvation does not significantly increase the effective steric demand of theorganic fragment, whilst maximising R-Li contacts.B. Internal solvation is sterically demanding, which forces larger rings to be adopted.OC. The organolithium deprotonates the Lewis base, leading to loss of reagent and sosmaller rings.OD. Internal solvation disrupts the normal solvation sphere, leading to lower coordinationnumbers at Li.

beta-H elimenation recation occurs when there is any beta-H present in the co-ordinated ligand with…

Answered: For each of the following pairs of…

For each of the following pairs of complexes, which is least likely to undergo b-hydride elimination? Choose only one from each pair.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Coordination Chemistry

It is a part of chemistry, in which the study of compounds that have central atoms surrounded by molecules or ions, known as ligand, is known as coordination chemistry.

Question

For each of the following pairs of complexes, which is least likely to undergo b-hydride elimination?
Choose only one from each pair.
ML
A
LMT
A
C
Select one:
a.
Me
Me
O b.
O C.
O d.
or
Ph3P
ос
ML
Me
or
Ph3P
OC
Identify complexes A and B and processes 1 and 2:
H3C-CH3
1
A
H
CI
B
A
Ph3PCI
OC
A
LM
A HIKIC
CO
PPh3
CI
Ph3P Ir-
PPh3
OC
PPh3
D
CO
PPh3
Ph3P
OC
H
.. Et
Ph3P
OC
PhaPr
OC
Pha
B
OC
PPh 3
BH
CI
PhaPr
OC
B
Pi...
B
H
LM
Pr
CI
Pri
CI
PPh3
H
PPh3
MCI
PPh3
E
PPh3
-M-
G
Pr
Pr
Pr
2
or
or
LM
1
Ligand
Substitution
Oxidative
Addition
F
Oxidative
Addition
B
1
Ligand
Substitution
H
Time left 103:15:10
Reductive
Elimination
B-Hydride
Elimination
2
Reductive
Elimination
2
B-Hydride
Elimination

For the reaction of the sodium enolate with chlorotrimethylsilane shown below, what is the
thermodynamic driving force for this reaction?
+ CISiMe3
Me Si-O
NaO
+ NaCl
Select one:
A. The formation of strong covalent bonds between Sodium and Chloride ions.
B. The breaking of weak Na-O and Si-Cl bonds.
C. Silicon-oxygen silicon bonds are stronger than silicon-carbon single bonds.
D. The formation of the NaCl lattice and release of the lattice enthalpy, coupled with the
formation of a strong Si-O bond.
For organolithium clusters of the general formula (RLi)6, reaction with additional Lewis basic
donor ligands leads to deaggregation and formation of smaller rings than the 6 membered
rings seen in the original cluster. For internally solvated clusters, however, 6 membered rings
are possible. Why?
Select one:
O A. Internal solvation does not significantly increase the effective steric demand of the
organic fragment, whilst maximising R-Li contacts.
B. Internal solvation is sterically demanding, which forces larger rings to be adopted.
OC. The organolithium deprotonates the Lewis base, leading to loss of reagent and so
smaller rings.
OD. Internal solvation disrupts the normal solvation sphere, leading to lower coordination
numbers at Li.

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