For each of the following draw a constitutional isomer of the most favorable product(s). Note: Some products will have tetrahedral stereocenters. Indicate them with an asterisk(*), but, there is no need to draw all the strereoisomers for this exercise. Focus on the constitutional isomers.

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For each of the following draw a constitutional isomer of the most favorable product(s).
Note: Some products will have tetrahedral stereocenters. Indicate them with an asterisk(*), but, there is no need to draw all the strereoisomers for this exercise. Focus on the constitutional isomers.

### Chemical Reactions Involving Alkenes

**b) Reaction of an Alkene with Hydrogen Bromide**

- The chemical equation depicts an alkene with a double bond (C=C) reacting with hydrogen bromide (HBr). The structure is linear, with six carbon atoms represented as follows:
  
  ```
  C - C - C = C - C + HBr
  ```

- An arrow indicates the direction of the chemical reaction.

**c) Reaction of Cyclopentene with Hydrogen Bromide**

- This equation shows a cyclic alkene, specifically cyclopentene (represented as a five-sided ring with a double bond), reacting with hydrogen bromide (HBr):
  
  ```
  (Cyclopentene structure) + HBr
  ```

- Again, an arrow indicates the direction of the chemical reaction.

These reactions typically demonstrate the addition of HBr across the double bond, resulting in the formation of a haloalkane.
Transcribed Image Text:### Chemical Reactions Involving Alkenes **b) Reaction of an Alkene with Hydrogen Bromide** - The chemical equation depicts an alkene with a double bond (C=C) reacting with hydrogen bromide (HBr). The structure is linear, with six carbon atoms represented as follows: ``` C - C - C = C - C + HBr ``` - An arrow indicates the direction of the chemical reaction. **c) Reaction of Cyclopentene with Hydrogen Bromide** - This equation shows a cyclic alkene, specifically cyclopentene (represented as a five-sided ring with a double bond), reacting with hydrogen bromide (HBr): ``` (Cyclopentene structure) + HBr ``` - Again, an arrow indicates the direction of the chemical reaction. These reactions typically demonstrate the addition of HBr across the double bond, resulting in the formation of a haloalkane.
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