For each of the examples below, decide if X is a binomial random variable. If so, specify n and p. If not, explain why not. 1 2 (a) X = number of heads from flipping the same coin seventeen times, where the probability of a head (b) X ооооо ооо | O O O O O Yes, n = 2 and p = 0.5. Yes, n = 17 and p = 0.5. No, p is not the same from trial to trial. No, the "trials" are independent of each other. No, the "trials" are not independent of each other. 1 and the probability of a head for the other coin 2 number of heads from flipping two coins nine times each, where the probability of a head for one coin = Yes, n = 9 and p = 0.125. Yes, n = 2 and p = 0.125. No, the "trials" are independent of each other. No, p is not the same from trial to trial. No, the "trials" are not independent of each other. (c) X = number of cities in which it will rain tomorrow among five neighboring cities located within 15 miles of each other. Yes, n = 15 and p = 0.5. Yes, n = 5 and p = 0.5. No, p is not the same from trial to trial. No, the "trials" are independent of each other. No, the "trials" are not independent of each other. = (d) X = number of children who will get the flu this winter in a kindergarten class with 25 children. Yes, n = 10 and p = 0.5. Yes, n = 25 and p = 0.5. No, the "trials" are independent of each other. No, the "trials" are not independent of each other. No, p is not the same from trial to trial. пооооо 1 4
For each of the examples below, decide if X is a binomial random variable. If so, specify n and p. If not, explain why not. 1 2 (a) X = number of heads from flipping the same coin seventeen times, where the probability of a head (b) X ооооо ооо | O O O O O Yes, n = 2 and p = 0.5. Yes, n = 17 and p = 0.5. No, p is not the same from trial to trial. No, the "trials" are independent of each other. No, the "trials" are not independent of each other. 1 and the probability of a head for the other coin 2 number of heads from flipping two coins nine times each, where the probability of a head for one coin = Yes, n = 9 and p = 0.125. Yes, n = 2 and p = 0.125. No, the "trials" are independent of each other. No, p is not the same from trial to trial. No, the "trials" are not independent of each other. (c) X = number of cities in which it will rain tomorrow among five neighboring cities located within 15 miles of each other. Yes, n = 15 and p = 0.5. Yes, n = 5 and p = 0.5. No, p is not the same from trial to trial. No, the "trials" are independent of each other. No, the "trials" are not independent of each other. = (d) X = number of children who will get the flu this winter in a kindergarten class with 25 children. Yes, n = 10 and p = 0.5. Yes, n = 25 and p = 0.5. No, the "trials" are independent of each other. No, the "trials" are not independent of each other. No, p is not the same from trial to trial. пооооо 1 4
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![For each of the examples below, decide if X is a binomial random variable. If so, specify n and p. If not, explain why not.
1
2
(a) X
= number of heads from flipping the same coin seventeen times, where the probability of a head
(b) X
ооооо
ооо
| O O O O O
Yes, n = 2 and p = 0.5.
Yes, n = 17 and p = 0.5.
No, p is not the same from trial to trial.
No, the "trials" are independent of each other.
No, the "trials" are not independent of each other.
1
and the probability of a head for the other coin
2
number of heads from flipping two coins nine times each, where the probability of a head for one coin =
Yes, n = 9 and p = 0.125.
Yes, n = 2 and p = 0.125.
No, the "trials" are independent of each other.
No, p is not the same from trial to trial.
No, the "trials" are not independent of each other.
(c)
X = number of cities in which it will rain tomorrow among five neighboring cities located within 15 miles of each other.
Yes, n = 15 and p = 0.5.
Yes, n = 5 and p = 0.5.
No, p is not the same from trial to trial.
No, the "trials" are independent of each other.
No, the "trials" are not independent of each other.
=
(d) X = number of children who will get the flu this winter in a kindergarten class with 25 children.
Yes, n = 10 and p = 0.5.
Yes, n = 25 and p = 0.5.
No, the "trials" are independent of each other.
No, the "trials" are not independent of each other.
No, p is not the same from trial to trial.
пооооо
1
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7a6a7f9-c998-406c-bf64-dffb66295312%2Fdd761983-d61d-46fe-8f15-89cc132d674b%2Fsk0esu7_processed.png&w=3840&q=75)
Transcribed Image Text:For each of the examples below, decide if X is a binomial random variable. If so, specify n and p. If not, explain why not.
1
2
(a) X
= number of heads from flipping the same coin seventeen times, where the probability of a head
(b) X
ооооо
ооо
| O O O O O
Yes, n = 2 and p = 0.5.
Yes, n = 17 and p = 0.5.
No, p is not the same from trial to trial.
No, the "trials" are independent of each other.
No, the "trials" are not independent of each other.
1
and the probability of a head for the other coin
2
number of heads from flipping two coins nine times each, where the probability of a head for one coin =
Yes, n = 9 and p = 0.125.
Yes, n = 2 and p = 0.125.
No, the "trials" are independent of each other.
No, p is not the same from trial to trial.
No, the "trials" are not independent of each other.
(c)
X = number of cities in which it will rain tomorrow among five neighboring cities located within 15 miles of each other.
Yes, n = 15 and p = 0.5.
Yes, n = 5 and p = 0.5.
No, p is not the same from trial to trial.
No, the "trials" are independent of each other.
No, the "trials" are not independent of each other.
=
(d) X = number of children who will get the flu this winter in a kindergarten class with 25 children.
Yes, n = 10 and p = 0.5.
Yes, n = 25 and p = 0.5.
No, the "trials" are independent of each other.
No, the "trials" are not independent of each other.
No, p is not the same from trial to trial.
пооооо
1
4
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