For each monosaccharide: [1] determine all acetal and hemiacetal carbons; [2] select the anomeric carbon; [3] designate the compound as an a or ß anomer, 6 CH2OH 5. CH2OH O 1CH2OH OH H OH H a. 4 b. H H 12 OH OH H ÓH ÓH a. Carbon 1 is the hemiacetal carbon. Carbon 2 is the v acetal carbon. Carbon 4 is the v anomeric carbon. The compound is B b. Carbon 2 is the hemiacetal carbon. There is not an v acetal carbon. HI-

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Chapter1: Chemical Foundations
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For each monosaccharide: [1] determine all acetal and hemiacetal carbons; [2] select the anomeric
carbon; [3] designate the compound as an a or ß anomer,
6 CH2OH
5.
H
H
CH2OH O
1CH2OH
OH
OH
H
a.
4
b.
H
H
12
OH
ÓH
Но
H
ÓH
ÓH
a. Carbon 1 is the
hemiacetal carbon.
Carbon 2 is the v acetal carbon.
Carbon 4 is the v anomeric carbon.
The compound is B
b. Carbon 2 is the
hemiacetal carbon.
There is not an v acetal carbon.
Carbon 4 is the v anomeric carbon.
The compound is a v
I-
Transcribed Image Text:For each monosaccharide: [1] determine all acetal and hemiacetal carbons; [2] select the anomeric carbon; [3] designate the compound as an a or ß anomer, 6 CH2OH 5. H H CH2OH O 1CH2OH OH OH H a. 4 b. H H 12 OH ÓH Но H ÓH ÓH a. Carbon 1 is the hemiacetal carbon. Carbon 2 is the v acetal carbon. Carbon 4 is the v anomeric carbon. The compound is B b. Carbon 2 is the hemiacetal carbon. There is not an v acetal carbon. Carbon 4 is the v anomeric carbon. The compound is a v I-
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