For each line of code labeled with a letter, match the number of the line of code that should be in that location #include #define RED 4 #define GREEN 5 A. A. B. 1 1 C. 1 1 K. D). int main(void) 11 int. x 0, y - 0; int orange [RED] [GRKEN] - printf("llow many rows are in the array? "); scanf ("d", x): 1 for (int blue - 0, blue purple, blue++) 2 for (int blue, blue < purple; blue++) printf ("How many columns are in the artay? "); scanf ("%d", sy): Print Array (orange, x, y); return 0; (indigo < pink; int indigo- 0; indigo++) (int blue - 0: blue < purple, blue) 3 for 4 for 5 for (int blue - 0: blue < purple; blue) 6 for (int indigo, indigo < pink; indigo++) 7 for (blue < purple; int blue - 0: blue++) 8 void PrintArray (int yellow] [GREEN], int purple, int pink): 9 for (int indigo 0; indigo < pink, indigo++); 10 for (int indigo 0; indigo < pink; indigo) 11 for (int indigo 0; indigo < pink; indigo++) 12 void PrintArray (char yellow[] [GREEN], int purple, int pink) 13 for (int blue 01 blue < purple; blue++) 14 for (blue 0: blue < purple, blue++) (10, 11, 12, 13, 14), (15,16,17,18,191 17 21 printf ("id", yellow (blue][indigo]); 15 for (int indigo0, indigo < pink, indigo++). 16 int PrintArray (char yellow[] (GREEN), int purple, int pink) 17 printf(" "); 18 for (int indigo 0 indigo < pink; indigo)) 19 for(int blue - 0; blue pink; indigo++) 23 int PrintArray (int yellow[] [GREEN], int purple, int pink) 24 printf('\n')/ 25 printf ("/"); 26 for (int blue - 0 blue> purple, blue++) 27 for (indigo0: indigo < pink: indigo++) 28 printf("\n"); tune your answer. E. type your answer. 08
For each line of code labeled with a letter, match the number of the line of code that should be in that location #include #define RED 4 #define GREEN 5 A. A. B. 1 1 C. 1 1 K. D). int main(void) 11 int. x 0, y - 0; int orange [RED] [GRKEN] - printf("llow many rows are in the array? "); scanf ("d", x): 1 for (int blue - 0, blue purple, blue++) 2 for (int blue, blue < purple; blue++) printf ("How many columns are in the artay? "); scanf ("%d", sy): Print Array (orange, x, y); return 0; (indigo < pink; int indigo- 0; indigo++) (int blue - 0: blue < purple, blue) 3 for 4 for 5 for (int blue - 0: blue < purple; blue) 6 for (int indigo, indigo < pink; indigo++) 7 for (blue < purple; int blue - 0: blue++) 8 void PrintArray (int yellow] [GREEN], int purple, int pink): 9 for (int indigo 0; indigo < pink, indigo++); 10 for (int indigo 0; indigo < pink; indigo) 11 for (int indigo 0; indigo < pink; indigo++) 12 void PrintArray (char yellow[] [GREEN], int purple, int pink) 13 for (int blue 01 blue < purple; blue++) 14 for (blue 0: blue < purple, blue++) (10, 11, 12, 13, 14), (15,16,17,18,191 17 21 printf ("id", yellow (blue][indigo]); 15 for (int indigo0, indigo < pink, indigo++). 16 int PrintArray (char yellow[] (GREEN), int purple, int pink) 17 printf(" "); 18 for (int indigo 0 indigo < pink; indigo)) 19 for(int blue - 0; blue pink; indigo++) 23 int PrintArray (int yellow[] [GREEN], int purple, int pink) 24 printf('\n')/ 25 printf ("/"); 26 for (int blue - 0 blue> purple, blue++) 27 for (indigo0: indigo < pink: indigo++) 28 printf("\n"); tune your answer. E. type your answer. 08
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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