**Understanding Normal Confidence Intervals**In the image provided, we are tasked with determining the corresponding normal confidence interval for different levels of confidence. Each confidence interval is constructed using the same sample statistics.**Levels of Confidence and Corresponding Intervals:**1. **Confidence Level (c) = 0.85** - Interval: (54.5, 59.3) - The interval is displayed on a number line ranging from 53 to 61, with the mean (x̄) marked at 56.9. The arrows indicate the span of the confidence interval from 54.5 to 59.3.2. **Confidence Level (c) = 0.90** - Interval: (54.9, 58.9) - This interval is also shown on a similar number line. The mean remains at 56.9, and the interval is slightly narrower from 54.9 to 58.9.3. **Confidence Level (c) = 0.95** - Interval: (55.2, 58.6) - Here, the interval narrows further with bounds from 55.2 to 58.6, yet the mean stays consistent at 56.9.4. **Confidence Level (c) = 0.98** - Interval: (55.4, 58.4) - The most precise interval is illustrated, with the upper and lower bounds being closest together between 55.4 and 58.4, holding the mean at 56.9.**Task:**You need to match each confidence interval depicted above to its respective level of confidence.**Note:**These visual aids help in understanding how increasing the confidence level leads to narrower intervals, indicating more precision in estimating the true population parameter. Understanding these can be essential for students studying statistics and working with data analysis.

Given, The different level of confidence. i.e., 85%, 90%, 95% and 98%

For each level of confidence c below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics. 17.c=0.85 18. c=0.90 19. c=0.95 20. c=0.98 54.5 59.3 55.2 58.6 x= 56.9 x= 56.9 + 53 54 55 56 57 58 59 60 61 53 54 55 56 57 58 59 60 61 54.9 58.9 55.4 58.4 x= 56.9 x= 56.9 53 54 5 56 57 58 59 60 61 53 54 55 56 57 58 59 60 61 Drag each normal confidence interval given above to the level of confidence c. 17. 18. 19. 20.

For each level of confidence c below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics. 17.c=0.85 18. c=0.90 19. c=0.95 20. c=0.98 54.5 59.3 55.2 58.6 x= 56.9 x= 56.9 + 53 54 55 56 57 58 59 60 61 53 54 55 56 57 58 59 60 61 54.9 58.9 55.4 58.4 x= 56.9 x= 56.9 53 54 5 56 57 58 59 60 61 53 54 55 56 57 58 59 60 61 Drag each normal confidence interval given above to the level of confidence c. 17. 18. 19. 20.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The average salary of 64 employee was 5400. Using historical data, we will assume that the population standard deviation is 260. Find the 90% confidence interval for the population mean salary. Select one: O a. 5400 + 53.46 O b. 5400 + 57.58 O c. 5400 + 55.52 O d. 5400 + 51.41
For each level of confidence c below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics. 17. c = 0.85 18. c = 0.88 19. c = 0.95 什 + 55 56 55 什 55 55 56 56 56 57 57 56.9 57 57 57.6 58 58.1 58 58 58.2 58 59 59 59 59 6450 x = 59.9 x = 59.9 60 x = 59.9 60 x = 59.9 60 61 61 61 61 62.2 62 61.7 62 62 61.6 ... + 62 63 63 62.9 63 63 20. c = 0.99 + 64 64 64 64 SCO SC
A sample of 14 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 2 ounces with a standard deviation of 0.12 ounces. The population standard deviation is known to be 0.1 ounce. Which distribution should you use for this problem?Construct a 90% confidence interval for the population average weight of the candies. State the confidence interval.Construct a 98% confidence interval for the population average weight of the candies. State the confidence interval.
You measure the lifetime of a random sample of 64 tires of a certain brand. The sample mean is = 50 months. Suppose that the lifetimes for tires of this brand follow a Normal distribution, with unknown mean and standard deviation = 3.79 months A 99% confidence interval for is: a. 40.2 to 59.8. b. 48.39 to 51.61. c. 48.78 to 51.22. d. 49.8 to 50.2.
For each level of confidence c below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics. 17. c= 0.88 18. c= 0.90 19. c= 0.95 20. c= 0.99 54.5 60.7 55.2 60 x = 57.6 X = 57.6 53 54 55 56 57 58 59 60 61 62 53 54 55 56 57 58 59 60 61 62 55.6 59.6 55.7 59.5 x= 57.6 x = 57.6 <+ 53 54 55 56 57 58 59 60 61 62 53 54 55 56 57 58 59 60 61 62 Drag each normal confidence interval given above to the level of confidence c. 17. 18. 19. 20.
For each level of confidencec below, determine the corresponding nomal confidence interval. Assume each confidence interval is constructed for the same sample statistics. 17. c= 0.85 18. c= 0.90 19. c =0.95 20. c=0.98 53.4 58.4 54.1 57.7 53.8 58 x= 55.9 x= 55.9 x 55.9 ++ 52 53 54 55 56 57 58 59 60 52 53 54 55 56 57 58 59 60 52 53 54 55 56 57 58 59 60 54.4 57.4 X 55.9 52 53 -54 55 56 57 58 59 60 Drag each normal confidence interval given above to the level of confidence c. 17. 18. 19. 20.
Which of the following terms is added and subtracted to the sample mean in order to obtain a 90% confidence interval containing the population mean? 1.960 Vn 1.645o 1.645- 1.960o
A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard deviation was 5.6 yards. Which of the following is the 80% confidence interval for the mean length per bolt of carpet? O A. 75.8 to 76.6 O B. 72.62 to 79.78 O C. 71.61 to 80.79 D. 75.40 to 77.00
Find 90% confidence interval
For each level of confidence c below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics. 17. c = 0.88 18. c= 0.90 19. c = 0.95 20. c= 0.98 53.4 56.8 53 57.2 52.7 57.5 x = 55.1 x = 55.1 x = 55.1 + + <+ 51 52 53 54 55 56 57 58 59 51 52 53 54 55 56 57 58 59 51 52 53 54 55 56 57 58 59 53.5 56.7 x = 55.1 51 52 53 54 55 56 57 58 59