For each isotope, detemine i i transformation for the nucleus and show the nuclear reaction. it is stable. If it is not, predict the type of a. Y- 89 b. Мо- 90 с. Fe-62
For each isotope, detemine i i transformation for the nucleus and show the nuclear reaction. it is stable. If it is not, predict the type of a. Y- 89 b. Мо- 90 с. Fe-62
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Isotope Stability and Nuclear Reactions:**
For each isotope listed below, determine if it is stable. If it is not stable, predict the type of transformation for the nucleus and show the nuclear reaction.
- **a. Y - 89 (Yttrium-89)**
- **b. Mo - 90 (Molybdenum-90)**
- **c. Fe - 62 (Iron-62)**
By analyzing these isotopes, we can understand whether they are stable or unstable. If an isotope is unstable (radioactive), it will undergo nuclear decay to transform into a more stable form. There are various types of nuclear decay, such as alpha decay, beta decay, and gamma decay.
1. **Yttrium-89 (Y-89)**
- Analysis: Y-89 is a stable isotope of yttrium. It does not undergo radioactive decay under normal circumstances and, hence, does not require further analysis for nuclear transformation.
2. **Molybdenum-90 (Mo-90)**
- Analysis: Mo-90 is an unstable isotope of molybdenum. It undergoes beta decay to transform into a more stable isotope of niobium (Nb).
- Nuclear Reaction:
\[
_{42}^{90}Mo \rightarrow _{41}^{90}Nb + \beta^- + \bar{\nu}_e
\]
Here, \(\beta^-\) represents a beta particle (electron), and \(\bar{\nu}_e\) represents an electron antineutrino.
3. **Iron-62 (Fe-62)**
- Analysis: Fe-62 is an unstable isotope of iron. It undergoes beta decay to transform into a more stable isotope of cobalt (Co).
- Nuclear Reaction:
\[
_{26}^{62}Fe \rightarrow _{27}^{62}Co + \beta^- + \bar{\nu}_e
\]
Here, \(\beta^-\) represents a beta particle (electron), and \(\bar{\nu}_e\) represents an electron antineutrino.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd75e31df-4f53-40d7-ad9b-050ec57c1b0b%2F9b79d170-6b66-445d-9fb2-4d6cdb176bd2%2F1wt2ua_processed.png&w=3840&q=75)
Transcribed Image Text:**Isotope Stability and Nuclear Reactions:**
For each isotope listed below, determine if it is stable. If it is not stable, predict the type of transformation for the nucleus and show the nuclear reaction.
- **a. Y - 89 (Yttrium-89)**
- **b. Mo - 90 (Molybdenum-90)**
- **c. Fe - 62 (Iron-62)**
By analyzing these isotopes, we can understand whether they are stable or unstable. If an isotope is unstable (radioactive), it will undergo nuclear decay to transform into a more stable form. There are various types of nuclear decay, such as alpha decay, beta decay, and gamma decay.
1. **Yttrium-89 (Y-89)**
- Analysis: Y-89 is a stable isotope of yttrium. It does not undergo radioactive decay under normal circumstances and, hence, does not require further analysis for nuclear transformation.
2. **Molybdenum-90 (Mo-90)**
- Analysis: Mo-90 is an unstable isotope of molybdenum. It undergoes beta decay to transform into a more stable isotope of niobium (Nb).
- Nuclear Reaction:
\[
_{42}^{90}Mo \rightarrow _{41}^{90}Nb + \beta^- + \bar{\nu}_e
\]
Here, \(\beta^-\) represents a beta particle (electron), and \(\bar{\nu}_e\) represents an electron antineutrino.
3. **Iron-62 (Fe-62)**
- Analysis: Fe-62 is an unstable isotope of iron. It undergoes beta decay to transform into a more stable isotope of cobalt (Co).
- Nuclear Reaction:
\[
_{26}^{62}Fe \rightarrow _{27}^{62}Co + \beta^- + \bar{\nu}_e
\]
Here, \(\beta^-\) represents a beta particle (electron), and \(\bar{\nu}_e\) represents an electron antineutrino.
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