For each graph below, find an Euler circuit in the graph or explain why the graph does not have an Euler circuit. (a) Figure 9: An undirected graph has 6 vertices, a through f. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise. IHence, the top verter becomes the rightmost verter. From the bottom left verter, moving clockwise, the vertices in the pentagon shape are labeled: a, b, c, e, and f. Verter d is above verter e, below and to the right of vertex c. Undirected edges, line segments, are between the following vertices: b and e; b and a; b and f; b and e; a and e; a and d; a and f; e and d; e and f; d and e; and d and f. (b) g Figure 10: An undirected graph has 7 vertices, a through g. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise. Ilence, the top verter becomes the rightmost verter. From the bottom left verter, moving clockwise, the vertices and f. Verter d is above vertex e, below and to the right of verter e. Verter g is below verter e, above and to the right of verter f. Undirected edges, line segments, are between the following vertices: a and b; a and e; a and d; a and f; b and f; b and e; b and e; e and d; e and g; d and e; d and f; and f and g. the pentagon shape are labeled: a, b, c, e,
For each graph below, find an Euler circuit in the graph or explain why the graph does not have an Euler circuit. (a) Figure 9: An undirected graph has 6 vertices, a through f. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise. IHence, the top verter becomes the rightmost verter. From the bottom left verter, moving clockwise, the vertices in the pentagon shape are labeled: a, b, c, e, and f. Verter d is above verter e, below and to the right of vertex c. Undirected edges, line segments, are between the following vertices: b and e; b and a; b and f; b and e; a and e; a and d; a and f; e and d; e and f; d and e; and d and f. (b) g Figure 10: An undirected graph has 7 vertices, a through g. 5 vertices are in the form of a regular pentagon, rotated 90 degrees clockwise. Ilence, the top verter becomes the rightmost verter. From the bottom left verter, moving clockwise, the vertices and f. Verter d is above vertex e, below and to the right of verter e. Verter g is below verter e, above and to the right of verter f. Undirected edges, line segments, are between the following vertices: a and b; a and e; a and d; a and f; b and f; b and e; b and e; e and d; e and g; d and e; d and f; and f and g. the pentagon shape are labeled: a, b, c, e,
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:For each graph below, find an Euler circuit in the graph or explain why the graph
does not have an Euler circuit.
(a)
Figure 9: An undirected graph has 6 vertices, a through f. 5 vertices
are in the form of a regular pentagon, rotated 90 degrees clockwise. IHence,
the top verter becomes the rightmost verter. From the bottom left verter,
moving clockwise, the vertices in the pentagon shape are labeled: a, b, c,
e, and f. Verter d is above verter e, below and to the right of vertex c.
Undirected edges, line segments, are between the following vertices: b and
e; b and a; b and f; b and e; a and e; a and d; a and f; e and d; e and f; d
and e; and d and f.
(b)
g
Figure 10: An undirected graph has 7 vertices, a through g. 5 vertices
are in the form of a regular pentagon, rotated 90 degrees clockwise. Ilence,
the top verter becomes the rightmost verter. From the bottom left verter,
moving clockwise, the vertices
and f. Verter d is above vertex e, below and to the right of verter e. Verter
g is below verter e, above and to the right of verter f. Undirected edges, line
segments, are between the following vertices: a and b; a and e; a and d; a
and f; b and f; b and e; b and e; e and d; e and g; d and e; d and f; and f
and g.
the pentagon shape are labeled: a, b, c, e,
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