For each equation, pick the two consecutive integer values between which the solution falls. a. The solution to the equation 6" = 5500 is greater than and less than because 64 1296 and 65 7776. b. The solution to the equation 3" = 45 is greater than and less than 1 is 100 c. The solution to the equation 5" greater than and less than 1 and 5 125 3 2 because 5 %3| 25 1 d. The solution to the equation 2" is greater 62 than and less than

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question

4.8

**Mathematics: Finding Integer Bounds for Exponential Equations**

For each equation, determine two consecutive integer values between which the solution falls.

a. The solution to the equation \(6^x = 5500\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\) because \(6^4 = 1296\) and \(6^5 = 7776\).

b. The solution to the equation \(3^x = 45\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\).

c. The solution to the equation \(5^x = \frac{1}{100}\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\) because \(5^{-3} = \frac{1}{125}\) and \(5^{-2} = \frac{1}{25}\).

d. The solution to the equation \(2^x = \frac{1}{62}\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\).
Transcribed Image Text:**Mathematics: Finding Integer Bounds for Exponential Equations** For each equation, determine two consecutive integer values between which the solution falls. a. The solution to the equation \(6^x = 5500\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\) because \(6^4 = 1296\) and \(6^5 = 7776\). b. The solution to the equation \(3^x = 45\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\). c. The solution to the equation \(5^x = \frac{1}{100}\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\) because \(5^{-3} = \frac{1}{125}\) and \(5^{-2} = \frac{1}{25}\). d. The solution to the equation \(2^x = \frac{1}{62}\) is greater than \(\_\_\_\_\) and less than \(\_\_\_\_\).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning