For customers purchasing a refrigerator at a certain appliance store, let A be the event that the refrigerator was manufactured in the U.S., B be the event that the refrigerator had an icemaker, and C be the event that the customer purchased an extended warranty. Relevant probabilities are below. P(B | A) = 0.81 P(C |An B') = 0.64 P(A) = 0.70 P(B | A) = 0.89 P(C |An B) = 0.76 P(C | A'n B) = 0.69 P(C | A'n B') = 0.31 (a) Construct a tree diagram consisting of first-, second-, and third-generation branches and place an event label and appropriate probability next to each branch. 10.7 C, 0.24 10.8 B', 0.11 e 10.6 A, 0.70 C, 0.36 0.6 0.3 A' C, 0.31 0.8 V 0.3 B', 0.19 0.6 (b) Compute P(A n Bn C). (Round your answer to four decimal places.) 0.47348 (c) Compute P(Bn C). (Round your answer to four decimal places.) 0.64115 (d) Compute P(C). (Round your answer to four decimal places.) (e) Compute P(A | B n C), the probability of a U.S. purchase given that an icemaker and extended warranty are also purchased. (Round your answer to four decimal places.)

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Chapter1: Combinatorial Analysis
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part 1, first problem. part 2, part d and e

If P(B | A) > P(B), show that P(B' | A) < P(B'). [Hint: Add P(B' | A) to both sides of the given inequality and then use the fact that P(A | B) + P(A' | B) = 1.]
P(B | A) + P(B' | A) > P(B) + P(B' | A)
> P(B) + P(B' || A)
> P(B' | A)
V > P(B' | A)
P(B' | A) < P(B')
1 - P(B)
P(B')
Transcribed Image Text:If P(B | A) > P(B), show that P(B' | A) < P(B'). [Hint: Add P(B' | A) to both sides of the given inequality and then use the fact that P(A | B) + P(A' | B) = 1.] P(B | A) + P(B' | A) > P(B) + P(B' | A) > P(B) + P(B' || A) > P(B' | A) V > P(B' | A) P(B' | A) < P(B') 1 - P(B) P(B')
For customers purchasing a refrigerator at a certain appliance store, let A be the event that the refrigerator was manufactured in the U.S., B be the event that the refrigerator had an icemaker, and C be the event that the
customer purchased an extended warranty. Relevant probabilities are below.
P(B | A') =
P(C | A n B') = 0.64
P(A) = 0.70
P(B | A) = 0.89
= 0.81
P(C | A n B) = 0.76
P(C | A'n B) = 0.69
P(C | A'n B') = 0.31
(a) Construct a tree diagram consisting of first-, second-, and third-generation branches and place an event label and appropriate probability next to each branch.
0.7
C', 0.24
B
0.8
в, 0.11
0.6
A, 0.70
C', 0.36
0.6
0.3
A'
с, 0.31
0.8
0.3
B', 0.19
0.6
(b) Compute P(A n B n C). (Round your answer to four decimal places.)
0.47348
(c) Compute P(B n C). (Round your answer to four decimal places.)
0.64115
(d) Compute P(C). (Round your answer to four decimal places.)
(e) Compute P(A | B n C), the probability of a U.S. purchase given that an icemaker and extended warranty are also purchased. (Round your answer to four decimal places.)
Transcribed Image Text:For customers purchasing a refrigerator at a certain appliance store, let A be the event that the refrigerator was manufactured in the U.S., B be the event that the refrigerator had an icemaker, and C be the event that the customer purchased an extended warranty. Relevant probabilities are below. P(B | A') = P(C | A n B') = 0.64 P(A) = 0.70 P(B | A) = 0.89 = 0.81 P(C | A n B) = 0.76 P(C | A'n B) = 0.69 P(C | A'n B') = 0.31 (a) Construct a tree diagram consisting of first-, second-, and third-generation branches and place an event label and appropriate probability next to each branch. 0.7 C', 0.24 B 0.8 в, 0.11 0.6 A, 0.70 C', 0.36 0.6 0.3 A' с, 0.31 0.8 0.3 B', 0.19 0.6 (b) Compute P(A n B n C). (Round your answer to four decimal places.) 0.47348 (c) Compute P(B n C). (Round your answer to four decimal places.) 0.64115 (d) Compute P(C). (Round your answer to four decimal places.) (e) Compute P(A | B n C), the probability of a U.S. purchase given that an icemaker and extended warranty are also purchased. (Round your answer to four decimal places.)
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