For combustion of propane the equation is C3H8(g) + O2(g) CO2(g) + H2O(g) AH = -24.82 kcal/mol a) Balance the equation b) Write the rate equation for the forward reaction. c) Write the rate equation for the reverse reaction. d) Write the equilibrium constant expression. e) How many kcal will be given off by burning 44 grams of C3H8 ?

General, Organic, and Biological Chemistry
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ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter9: Chemical Reactions
Section: Chapter Questions
Problem 9.63EP: Consider the following equilibrium system. N2(g)+O2(g)2NO(g) a. Write the chemical equation for the...
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-. For combustion of propane the equation is C3H8(g) + O2(g) CO2(g) + H2O(g) AH = -24.82 kcal/mol
a) Balance the equation
b) Write the rate equation for the forward reaction.
c) Write the rate equation for the reverse reaction.
d) Write the equilibrium constant expression.
e) How many kcal will be given off by burning 44 grams of C3H8 ?
Transcribed Image Text:-. For combustion of propane the equation is C3H8(g) + O2(g) CO2(g) + H2O(g) AH = -24.82 kcal/mol a) Balance the equation b) Write the rate equation for the forward reaction. c) Write the rate equation for the reverse reaction. d) Write the equilibrium constant expression. e) How many kcal will be given off by burning 44 grams of C3H8 ?
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