For cases where [A] exactly doubles: • if the rate does not change, the order for A is 0. • if the rate doubles, then the order for A is 1. •if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: order [reactant], = (- ` [reactant], ratej rate2 What is the reaction order with respect to A? [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.424 0.801 0.126 Trial 2 0.848 0.801 0.253 Trial 3 0.424 1.60 0.506 Trial 4 0.249 0.244 0.00689 Rate = k[A]orderArB]orderB

For cases where [A] exactly doubles: • if the rate does not change, the order for A is 0. • if the rate doubles, then the order for A is 1. •if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: order [reactant], = (- ` [reactant], ratej rate2 What is the reaction order with respect to A? [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.424 0.801 0.126 Trial 2 0.848 0.801 0.253 Trial 3 0.424 1.60 0.506 Trial 4 0.249 0.244 0.00689 Rate = k[A]orderArB]orderB

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Calculations for standardization of sodium hyroxide Mass of KHCgH404 (9) Moles of KHC₂H404 used (mol) Moles of NaOH reacted (mol) Final buret reading of NaOH (mL) Initial buret reading of NaOH (mL) Volume of NaOH solution used (mL) Volume of NaOH solution used (L) Concentration of NaOH (M) Trial 1 0.424 .0021 40.89 19.29 21.60 .0216 Trial 2 0.439 .0021 22.09 0.95 21.14 .02114 Table view List view Trial 3 0.449 .0022 49.10 22.09 27.01 .02701
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