For bound states: On (z) = Bekzz for z < - 1/1 A cos(k₂z){sin(k₂z)} for − << 1/1, Be-k₂z - for z > 1/1, where k₂ = √√2m, E/ ħ² and k₂ = √2mµ(V。 — E)/ ħ². kz For the even cosine solutions: - For the odd sine solutions: (k₂/mд) tan (쏠) = K₂/mĮ = -K₂/ml (k₂/mj) cot (쏠) Exercise 4: Derive these equations.
For bound states: On (z) = Bekzz for z < - 1/1 A cos(k₂z){sin(k₂z)} for − << 1/1, Be-k₂z - for z > 1/1, where k₂ = √√2m, E/ ħ² and k₂ = √2mµ(V。 — E)/ ħ². kz For the even cosine solutions: - For the odd sine solutions: (k₂/mд) tan (쏠) = K₂/mĮ = -K₂/ml (k₂/mj) cot (쏠) Exercise 4: Derive these equations.
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 27PT: Find the unknown value. 27. y varies jointly with x and the cube root of 2. If when x=2 and...
Question

Transcribed Image Text:For bound states:
On (z) =
Bekzz
for z < - 1/1
A cos(k₂z){sin(k₂z)} for − << 1/1,
Be-k₂z
-
for z > 1/1,
where k₂ = √√2m, E/ ħ² and k₂ = √2mµ(V。 — E)/ ħ².
kz
For the even cosine solutions:
-
For the odd sine solutions:
(k₂/mд) tan
(쏠)
= K₂/mĮ
= -K₂/ml
(k₂/mj) cot (쏠)
Exercise 4: Derive these equations.
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