For aumbersl& 2, censider the reaction: 3 NaOH(aq) + FeCl, (4) 3 Naci (aq) + PefOH)» (s) (molar mass: Fe (OH)s-106.84 g/mole; FeCls 162.19 g/mole) 1. What mass of Fe (OH)a would be produced if 300 ml, of 0,150 M NaOH were added to a solution containing excess FeCls? 2. What volume of 1.6M NAOH will react with 33.0 g of FeCla? 3, What is the concentration of 22.50 mi of NaOH if this was neutralized with 20.50 mL of 0.150 M HCI in the following reaction? NAOH + HCI - Naci + H20

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.104QE: A 10.00-mL sample of a 24.00% solution of ammonium bromide (NH4Br) requires 23.41 mL of 1.200 molar...
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Directions: Read and solve the following problems carefully and completely. Use
a separate sheet of paper to show your selutions and anawers.
For aumbers 1 & 2, consider the reaction:
3 NaOH(aq) + FeCla (s)
- 3 NaCI (aq) + Pe(OH)» (*)
(molar mass: Fe (OH)3 - 106.84 g/mole; FeCis- 162.19 g/mole)
For
1. What mass of Fe (OH would be produced if 300 ml, of 0,150 M NAOH
were added to a nolution containing excess FeCls?
2. What volume of 1.6M NAOH will react with 33.0 g of FeCl?
3, What is the concentration of 22.50 mi of NaOH if this was neutralized with
20.50 mL of 0.150 M HCI in the following reaction?
Ma
4. H
NaOH + HCI -+ Naci + H20
4. What volume of 2.25M H2SO4 should be diluted with water to prepare 1.5 Lof
1.20 M acid?
B.
C.
Activity #2: Multiple Choice:
Directions: Read the following and select the BEST answer from the cheices.
D.
Write your answer on a separate sheet of paper.
5. Hou
A.T
1. The concentration (M) uf an aqueous sodium hydroxide produced when 0.200
Lof a 2.0 M solution was diluted to 0,800L is
B.T
B. 0.30
C. 0.40
D. 0.50
A. 0.2
2. How many grams of CHaOH must be added to water te prepare 150 ml of a
C.T
solution that is 2.0 M CH,OH?
B. 9.6 g
C. 8.6 g
D. 9.0 g
D.
A. 10.1 g
3. Which of the following is TRUE about dilution?
6. Hot
1. The number of moles of solute changes the volume of the solution chang
A.
IL. The number of moles of solute does not change. o
IN. The final volume of the solution increases.
Transcribed Image Text:Directions: Read and solve the following problems carefully and completely. Use a separate sheet of paper to show your selutions and anawers. For aumbers 1 & 2, consider the reaction: 3 NaOH(aq) + FeCla (s) - 3 NaCI (aq) + Pe(OH)» (*) (molar mass: Fe (OH)3 - 106.84 g/mole; FeCis- 162.19 g/mole) For 1. What mass of Fe (OH would be produced if 300 ml, of 0,150 M NAOH were added to a nolution containing excess FeCls? 2. What volume of 1.6M NAOH will react with 33.0 g of FeCl? 3, What is the concentration of 22.50 mi of NaOH if this was neutralized with 20.50 mL of 0.150 M HCI in the following reaction? Ma 4. H NaOH + HCI -+ Naci + H20 4. What volume of 2.25M H2SO4 should be diluted with water to prepare 1.5 Lof 1.20 M acid? B. C. Activity #2: Multiple Choice: Directions: Read the following and select the BEST answer from the cheices. D. Write your answer on a separate sheet of paper. 5. Hou A.T 1. The concentration (M) uf an aqueous sodium hydroxide produced when 0.200 Lof a 2.0 M solution was diluted to 0,800L is B.T B. 0.30 C. 0.40 D. 0.50 A. 0.2 2. How many grams of CHaOH must be added to water te prepare 150 ml of a C.T solution that is 2.0 M CH,OH? B. 9.6 g C. 8.6 g D. 9.0 g D. A. 10.1 g 3. Which of the following is TRUE about dilution? 6. Hot 1. The number of moles of solute changes the volume of the solution chang A. IL. The number of moles of solute does not change. o IN. The final volume of the solution increases.
wV. The final concentration of the solution will be lesser than the initial
concentration of the solution,
A.I enly
C. I and II
B.I, II & III
D. II, III & IV
For numbers 4 - 6, refer to the chemical equation and dingram below for your
answer in the following questions.
3NAOH(aq) + Al(NO3)a (aq)
3NANO3
+ Al(OH):(aq)
2.1 M NAOH 1.3 g Al(NO3)3
Volume
Mass of Al(NOs)a
Mole Al{NOs)a
Mole NaOH
NaOH
G1- vot
4. How is the number of moles of Al(NOala determined given its mass?
A. The mass (g) of Al(NOa)a is divided by its molar masn (g/mol).
B. The mass (g) of Al(NO.)s is added to its molar mass (g/mol).
C. The mass (g) of Al(NO3)a is subtracted to its molar mass
(g/mol)
D. All of the above
5. How to solve for the number of molea of NaOH? l
A. The mass (g) of Al(NOa)a is added to its molar mass, then multiply to the
molar ratio of NaOH and Al(NOala.
B. The mass (g) of Al(NOa)a is divided by its molar mass, then multiply to the
molar ratio of NAOH and Al(NOala
C. The mass (g) of Al(NOa)a is divided by its molar masa, then added to the
molar ratio of NaOH and Al(NO.,
D. The molar mass of Al(NO3)a is added to its molar mas, then added to the
molar ratio of NAOH and Al(NOaja,
6. How can the volume of NAOH be deteramined?
A. The number of molen of NaOH is added to the molar concentration of NaOH.
11
Transcribed Image Text:wV. The final concentration of the solution will be lesser than the initial concentration of the solution, A.I enly C. I and II B.I, II & III D. II, III & IV For numbers 4 - 6, refer to the chemical equation and dingram below for your answer in the following questions. 3NAOH(aq) + Al(NO3)a (aq) 3NANO3 + Al(OH):(aq) 2.1 M NAOH 1.3 g Al(NO3)3 Volume Mass of Al(NOs)a Mole Al{NOs)a Mole NaOH NaOH G1- vot 4. How is the number of moles of Al(NOala determined given its mass? A. The mass (g) of Al(NOa)a is divided by its molar masn (g/mol). B. The mass (g) of Al(NO.)s is added to its molar mass (g/mol). C. The mass (g) of Al(NO3)a is subtracted to its molar mass (g/mol) D. All of the above 5. How to solve for the number of molea of NaOH? l A. The mass (g) of Al(NOa)a is added to its molar mass, then multiply to the molar ratio of NaOH and Al(NOala. B. The mass (g) of Al(NOa)a is divided by its molar mass, then multiply to the molar ratio of NAOH and Al(NOala C. The mass (g) of Al(NOa)a is divided by its molar masa, then added to the molar ratio of NaOH and Al(NO., D. The molar mass of Al(NO3)a is added to its molar mas, then added to the molar ratio of NAOH and Al(NOaja, 6. How can the volume of NAOH be deteramined? A. The number of molen of NaOH is added to the molar concentration of NaOH. 11
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