Answered: For atomic hydrogen calculate the…

For atomic hydrogen calculate the frequency of the photon released when an electron makes a transition from the 4th state to the 2nd state.

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Question

For atomic hydrogen, calculate the frequency of the photon released when an electron makes a transition from the 4th state to the 2nd state.

Expert Solution

Concept and Principle:

Electrons are capeable of moving from one state to another. When an electron in a higher state comes down to a lower state it will do so by releasing a photon. This creates emission lines.

The wavelength of the emitted photon is given by the Rydberg formula,

$λ = \frac{1}{R_{\infty}} (\frac{n_{1}^{2} n_{2}^{2}}{n_{1}^{2} - n_{2}^{2}})$

Here R_∞ is the Rydberg constant and has a value of 1.097373 × 10⁷ m^-1, and n₁ and n₂ are the states in which transition takes place.

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