For any triangle ABC with angles with positive measures mZA, mZB, and mZC and side lengths of a, b, and c with the relative positions as shown in the diagram below select the following statements that are true. In other words, select all of the following that represent either form of the Law of Cosines. B A Select all the equalities that are true. Oa? = 6° + c² – 2bc - cos(m/A) a? – 6? – c? | cos(m/A) : -2bc c2 – a? – b? cos(m/C) = cos(m/A) cos(m/B) - 2ab a b cos(m/B) cos(m/C) O2 = a² + b? – 2ab · cos(m/C) - O62 = a? + c 2ac · cos(m/B) cos(mLA) cos(m/C) - a 62 – a? – c? O cos(m/B) = - 2ac

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
For any triangle ABC with angles with positive measures mZA, mZB, and mZC and side lengths of a, b, and c with the relative positions as
shown in the diagram below select the following statements that are true.
In other words, select all of the following that represent either form of the Law of Cosines.
B
A
Select all the equalities that are true.
Oa? = 6° + c² – 2bc - cos(m/A)
a? – 6? – c?
| cos(m/A) :
-2bc
c2 – a? – b?
cos(m/C) =
cos(m/A)
cos(m/B)
- 2ab
a
b
cos(m/B)
cos(m/C)
O2 = a² + b? – 2ab · cos(m/C)
-
O62 = a? + c
2ac · cos(m/B)
cos(mLA)
cos(m/C)
-
a
62 – a? – c?
O cos(m/B) =
- 2ac
Transcribed Image Text:For any triangle ABC with angles with positive measures mZA, mZB, and mZC and side lengths of a, b, and c with the relative positions as shown in the diagram below select the following statements that are true. In other words, select all of the following that represent either form of the Law of Cosines. B A Select all the equalities that are true. Oa? = 6° + c² – 2bc - cos(m/A) a? – 6? – c? | cos(m/A) : -2bc c2 – a? – b? cos(m/C) = cos(m/A) cos(m/B) - 2ab a b cos(m/B) cos(m/C) O2 = a² + b? – 2ab · cos(m/C) - O62 = a? + c 2ac · cos(m/B) cos(mLA) cos(m/C) - a 62 – a? – c? O cos(m/B) = - 2ac
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