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Probability
For any three events A, B and C P ( A U BUC) = P(A) + P (B ) + P ( C ) – P ( A OB)-P( BnC) -P(CnA)+ P (A BnC)

For any three events A, B and C P ( A U BUC) = P(A) + P (B ) + P ( C ) – P ( A OB)-P( BnC) -P(CnA)+ P (A BnC)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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: For any three events A, B and C P ( A U BUC) = P ( A ) + P ( B ) + P ( C ) – P ( A O B ) – P ( BnC) -P(CnA) + P (AO BOC)
Transcribed Image Text:: For any three events A, B and C P ( A U BUC) = P ( A ) + P ( B ) + P ( C ) – P ( A O B ) – P ( BnC) -P(CnA) + P (AO BOC)
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