For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed.
For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Language is C++
Transcribed Image Text:19
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24 }
/* Your solution goes here */
cout << endl;
return 0;
Transcribed Image Text:For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If
keysList = {42, 105, 101, 100) and itemsList={10, 20, 30, 40}, print:
20 30
Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed.
Code writing challenge activity demo
458626.3144760.qx3zqy7
1 #include <iostream>
2 #include <vector>
3 using namespace std;
4
5 int main() {
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18
const int SIZE_LIST = 4;
vector<int> keysList (SIZE_LIST);
vector<int> itemsList (SIZE_LIST);
unsigned int i;
for (i = 0; i < keysList.size(); ++i) {
cin >> keysList.at(i);
}
for (i = 0; i < itemsList.size(); ++i) {
cin >> itemsList.at(i);
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passed
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