For an invertible matrix A, prove that A and A-1 have the same eigenvectors. How are the eigenvalues of A related to the eigenvalues of A-1? Letting x be an eigenvector of A gives Ax = 1x for a corresponding eigenvalue 2. Using matrix operations and the properties of inverse matrices gives which of the following? Ax = Ax Ax = Ax Ax = Ax AxA-1 = AxA-1 = A-1x Ax = ix A-1Ax = A-1x Ix = AA-1x Ax/A = Ax/A A/(Ax) = A/(Ax) (A/A)x = (A/2)x Ix = (A/A)x x = AA-1x OXAA-1 xI = 1A-1x x = AA-1x O(A/A)x = ixA-1 Ix = ixA-1 x = AA-1x x = AxA-1 1x A-1x = 1x A-1x = 1x A-1x = 1x A-1x = This shows that ---Select--- vis an eigenvector of A-1 with eigenvalue --Select--- v Select-- Need Help? 1/x 1/2 ed Work Revert to Last Response

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