Given Anova is used among three treatments.
So number of treatments = k = 3.
degree of freedom between treatments =k-1 = 3-1 =2
sample size of 5 in each treatment. So n1 = 5 n2 = 5 n3 = 5
Total sample size = N =n1+ n2+n3 = 5+5+5=15
Degree of freedom within treatments = N-k = 15-3 = 12
So the Anova has a distribution F with degree of freedoms 2,15---F2,15
