For an ARIMA(O,1,1) model, the critical value (or rejection region value) that the test statistic, Q, would be compared to for a test at the 0.05 level of significance with 10 lags would be
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- The leader of two postpartum women’s support groups is interested in the depression levels of the women in her groups. She administers the Center for Epidemiologic Studies Depression Scale (CES-D) screening test to the members of her groups. The CES-D is a 20-question self-test that measures depressive feelings and behaviors during the previous week. The mean depression level from the screening test for the 10 women in the first group is μ₁ = 16; the mean depression level for the 14 women in the second group is μ₂ = 10. Without calculating the weighted mean for the combined group, you know that the weighted mean is:A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. Purchase Rating Individual After Before 1 6 5 6 4 3 7 4 4 3 3 8 8 6 State the null and alternative hypotheses. (Use u, = mean rating after - mean rating before.) O Ho: Hs0 H3: H = 0 O Ho: Hd#0 Hai Hq= 0 O Ho: Hg=0 O Ho: Hd> 0 Calculate the value of the test statistic. (Round your answer to three decimal places.) 1.183 Calculate the p-value. (Round your answer to…A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a = .05 and the following data to test the hypothesis and comment on the value of the commercial. Purchase Rating Purchase Rating Individual After Before Individual After Before 1 6. 6. 3 2 6. 4 6. 7 8 7 6. 5 4 4 8 6. 6 a. What are the hypotheses? Ho: ld is Select Ha: ld is select b. Compute d (to 3 decimals). Compute sa (to 1 decimal).
- Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x= 99.11, y = 100.1, r=0.872, P-value = 0.000, and y = 7.99 +0.93x, where x represents the IQ score of the twin bom first. Find the best predicted value of y given that the twin born first has an IQ of 96? Use a significance level of 0.05. 1 Critical Values of the Pearson Correlation Coefficient r E Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is. Critical Values of the Pearson Correlation Coefficient r a = 0.01 NOTE: To test Ho: p=0 against H,: p#0, reject H, if the absolute value of r is greater than the critical value in the table. (Round to two decimal places as needed.) a = 0.05 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.834 0.798 0.765 0.735 0.708 8 0.707 9 0.666 10 0.632 11 0.602 0.576 0.553 12 0.684 13 0.661 0.641 0.623 0.606 14 0.532 0.514 15 16 17 0.497 0.482 0.468 0.456 0.444 0.590 0.575…The heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. (show all work) To be considered extremely tall, a woman’s height must fall in the top 2% for all heights of women. What is the benchmark height for this designation? To be considered extremely short, a woman’s height must fall in the bottom 2% for all heights of women. What is the benchmark height for this designation?A small pilot study is run to compare a new drug for chronic pain to one that is currently available. Participants are randomly assigned to receive either the new drug or the currently available drug and to report improvement in pain on a 5-point ordinal scare: 1= pain is much worse,2=pain is slightly worse,3=no change,4=pain improved slightly,5= pain much improved.Is there a significance difference in self reported improvement in pain? Use the Mann-Whitney U test with a 5% level of significance. New Drug: 4 5 3 3 4 2 Standard Drug: 2 3 4 1 2 3
- To determine if there is gender and/or race discrimination in car buying, a researcher put together a team of white males, black males, white females, and black females who were each asked to obtain an initial offer price from the dealer on a certain model car. The accompanying data are based on the results and represent the profit on the initial price offered by the dealer. Previous testing resulted in rejecting Ho: PWM HBM =HWF = HBF and concluding that the mean profit for the four race-gender groups differ. Use Tukey's test to determine which pairwise means differ using a familywise error rate of a = 0.05. Click the icon to view the data table. Use Tukey's test to determine which pairwise means differ using a familywise error rate of a = 0.05. Find the Tukey 95% simultaneous confidence intervals for all pairwise comparisons. The interval for the pairwise comparision HBM HWM is The interval for the pairwise comparision pwFPWM is The interval for the pairwise comparision HBF HWM is…A study was conducted using 50 mobile network users who volunteered to participate in a research as the entry of the third telco player in the country is on its way. One of the variables studied was the data connection speed in the previous month. Based on the data in the following table, is there a significant difference between the connectivity speeds of the two present mobile networks during the previous month? Use a 5% level of significance and assume that the population variances are equal. 1. The alternative hypothesis for the test would be? 2. The alternative hypothesis for the test would be? 3. What is the computed value of the test statistic? 4. What would be your decision?In a random sample of males, it was found that 29 write with their left hands and 212 do not. In a random sample of females, it was found that 70 write with their left hands and 444 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below.
- Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on arganisms, an expert claimed that the amount of gamma radiation needed to sterilize a colany of tardigrades no longer has a mean of 1200 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy.) A study was conducted on a sample of 21 randomly selected tardigrade colonies, finding that the amount of gamma radiation needed to sterilize a colony had a sample mean af 1225 Gy, with a sample standard deviation of 65 Gy. Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level af significance, to support the claim that H, the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is nat equal to 1200 Gy. (a) State the null hypothesis and the…n 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 25 30 35 40 45 50 60 70 80 90 100 n x=0.05 0.950 0.878 0.811 0.754 0.707 0.666 0.632 0.602 0.576 0.553 0.532 0.514 0.497 0.482 0.468 0.456 0.444 0.396 0.361 0.335 0.312 0.294 0.279 0.254 0.236 0.220 0.207 0.196 α = 0.05 α = 0.01 0.990 0.959 0.917 0.875 0.834 0.798 0.765 0.735 0.708 0.684 0.661 0.641 0.623 0.606 0.590 0.575 0.561 0.505 0.463 0.430 0.402 0.378 0.361 0.330 0.305 0.286 0.269 0.256 α = 0.01 NOTE: To test Ho: p=0 against H₁: p0, reject Ho if the absolute value of ris greater than the critical value in the table.Select all that apply: We should reject H0. We should not reject H0. At the 1% significance level, the data do not provide sufficient evidence to conclude that the amount of time American teenagers watch television per week is different from 14.1 hours. At the 1% significance level, the data provide sufficient evidence to conclude that the amount of time American teenagers watch television per week is different from 14.1 hours.