For all sets A and B, determine whether each of the statement is true or false.

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For discrete math please do A and B

### Determining the Truth of Set Theory Statements

In set theory, we often work to determine the truth or falsehood of various propositions. Below, we analyze two such statements, prove if they are true, or find counterexamples if they are false. Algebraic laws relevant to set operations are utilized in the proofs.

**Problem Statement:**

For all sets \( A \) and \( B \), determine whether each of the statements below is true or false. If it is true, then prove it algebraically indicating the laws used. If it is false, then find a counterexample.

(a) \( \mathcal{P}(A) \cup \mathcal{P}(B) = \mathcal{P}(A \cup B) \). (Note: \( \mathcal{P}(A) \) is the power set of set \( A \).)

(b) \( (A - B) \cup (B - A) = (A \cup B) - (A \cap B) \).

### Explanation of Terms:

- **Power Set \( \mathcal{P}(A) \)**: The set of all subsets of a set \( A \).

- **Set Difference \( A - B \)**: The set of elements that are in \( A \) but not in \( B \).

- **Union \( A \cup B \)**: The set of elements that are in \( A \), in \( B \), or in both.

- **Intersection \( A \cap B \)**: The set of elements that are in both \( A \) and \( B \).

### Analysis:

#### (a) Power Set Union

\[ \mathcal{P}(A) \cup \mathcal{P}(B) = \mathcal{P}(A \cup B) \]
To determine if this statement is true, consider the following:

- **Right-hand side \( \mathcal{P}(A \cup B) \)**: Includes all subsets of \( A \cup B \).

- **Left-hand side \( \mathcal{P}(A) \cup \mathcal{P}(B) \)**: Includes all subsets of \( A \) and all subsets of \( B \).

Since \( \mathcal{P}(A \cup B) \) contains all subsets formed by elements in either \( A \) or \( B \) and more besides, this statement is
Transcribed Image Text:### Determining the Truth of Set Theory Statements In set theory, we often work to determine the truth or falsehood of various propositions. Below, we analyze two such statements, prove if they are true, or find counterexamples if they are false. Algebraic laws relevant to set operations are utilized in the proofs. **Problem Statement:** For all sets \( A \) and \( B \), determine whether each of the statements below is true or false. If it is true, then prove it algebraically indicating the laws used. If it is false, then find a counterexample. (a) \( \mathcal{P}(A) \cup \mathcal{P}(B) = \mathcal{P}(A \cup B) \). (Note: \( \mathcal{P}(A) \) is the power set of set \( A \).) (b) \( (A - B) \cup (B - A) = (A \cup B) - (A \cap B) \). ### Explanation of Terms: - **Power Set \( \mathcal{P}(A) \)**: The set of all subsets of a set \( A \). - **Set Difference \( A - B \)**: The set of elements that are in \( A \) but not in \( B \). - **Union \( A \cup B \)**: The set of elements that are in \( A \), in \( B \), or in both. - **Intersection \( A \cap B \)**: The set of elements that are in both \( A \) and \( B \). ### Analysis: #### (a) Power Set Union \[ \mathcal{P}(A) \cup \mathcal{P}(B) = \mathcal{P}(A \cup B) \] To determine if this statement is true, consider the following: - **Right-hand side \( \mathcal{P}(A \cup B) \)**: Includes all subsets of \( A \cup B \). - **Left-hand side \( \mathcal{P}(A) \cup \mathcal{P}(B) \)**: Includes all subsets of \( A \) and all subsets of \( B \). Since \( \mathcal{P}(A \cup B) \) contains all subsets formed by elements in either \( A \) or \( B \) and more besides, this statement is
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