For acetic acid in aqueous solution at 298 K the dissociation reaction is CH-C0ОН (аq) + H,0() = CH3C00¯(aq)+ H30*(aq) With pka = 4.75. %3D To simplify calculations, denote a = [CH3COOH], b=[CH3COO] and x = Consider a solution of total concentration c= 0.1 M. [H3O*]. %3D Use the two equations: bx Ka аnd a +b %3с a a.Solve for a as a function of Ka, c and x, then for b use b = c-a. b.Write an equation the fractional population of the acid fa, in terms of K and x, by substituting results of point a below: fa = %3D a a+b Of course, fb = b/c = 1– fa.

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Chapter1: Chemical Foundations
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3.Composition of acetic acid solution
For acetic acid in aqueous solution at 298 K the dissociation reaction is
CH3COOH(aq) + H20(l) = CH3C00 (aq) + H30*(aq)
With pka = 4.75.
To simplify calculations, denote a = [CH3COOH], b=[CH3COO] and x = [H3O*].
Consider a solution of total concentrationc = 0.1 M.
Use the two equations:
bx
аnd a + b %3D с
а
a.Solve for a as a function of Ka, c and x, then for b use b = c- a.
b.Write an equation the fractional population of the acid fa, in terms of K and x, by
substituting results of point a below:
fa =
www
а
||
%3D
a+b
Of course, fb = b/c = 1– fa.
%3D
C.Make an Excel plot of fa vs. pH and fb vs. pH.
Use this plot to explain the chemical meaning of the value of pka.
Transcribed Image Text:3.Composition of acetic acid solution For acetic acid in aqueous solution at 298 K the dissociation reaction is CH3COOH(aq) + H20(l) = CH3C00 (aq) + H30*(aq) With pka = 4.75. To simplify calculations, denote a = [CH3COOH], b=[CH3COO] and x = [H3O*]. Consider a solution of total concentrationc = 0.1 M. Use the two equations: bx аnd a + b %3D с а a.Solve for a as a function of Ka, c and x, then for b use b = c- a. b.Write an equation the fractional population of the acid fa, in terms of K and x, by substituting results of point a below: fa = www а || %3D a+b Of course, fb = b/c = 1– fa. %3D C.Make an Excel plot of fa vs. pH and fb vs. pH. Use this plot to explain the chemical meaning of the value of pka.
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