For a week, a clothing company tracks the amounts spent by its customers, with the results shown to the right.a) What is the probability that a randomly chosen customer spent $120 or more?b) What is the probability that a randomly chosen customer did not spend less than $80?c) What is the probability that a randomly chosen customer spent between $40 and $159.99?a) What formula should be used to find the probability that a randomly chosen customer spent $120 or more?- \[ P(\text{120 or more}) = 1 - P(\text{120 - $159.99}) \]- \[ P(\text{120 or more}) = P(\text{120 - $159.99}) \]- \[ P(\text{120 or more}) = P(\text{120 - $159.99}) + P(\text{160 - $199.99}) + P(\text{\$200 or more}) \]- \[ P(\text{120 or more}) = 1 - P(\text{120 - $159.99}) + P(\text{160 - $199.99}) + P(\text{\$200 or more}) \]The probability that a randomly chosen customer spent $120 or more is $ \boxed{\frac{10}{32}} $ (Simplify your answer.)b) What formula should be used to find the probability that a randomly chosen customer did not spend less than $80?- \[ P(\text{not less than 80}) = P(S80 - \$119.99) \]- \[ P(\text{not less than 80}) = \frac{1}{1} - P(\text{120 - $159.99}) \]- \[ P(\text{not less than 80}) = \frac{1}{1} - P(\text{30 - $39.99}) + P(\text{40 - $79.99}) \]- \[ P(\text{not less than 80}) = P(\text{30 - $39.99}) + P(\text{40 - $79.99}) + P(\text{80 - $119.99}) \]The probability that a randomly customer did not spend less than $80 is $ \boxed{\frac{8}{32}} $(Simplify your answer.)c) What

Here given grouped frequency distribution of amount spent by customers of clothing company

Answered: For a week, a clothing company tracks…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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