For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth 2.87 in ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width 4.5. Calculate the velocity (v) in fps.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Can you please show how to do this problem? I’m confused on this homework question and please box answer and pleas write clear thank you.

**Problem Statement:**

For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth of 2.87 ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width is 4.5 ft. Calculate the velocity (v) in feet per second (fps).

**Explanation:**

To solve this problem, you would typically use the Manning's equation for open channel flow, which is given by:

\[ v = \frac{1}{n} R^{2/3} S^{1/2} \]

where:
- \( v \) = velocity (fps)
- \( n \) = Manning’s roughness coefficient
- \( R \) = hydraulic radius (ft)
- \( S \) = slope of the channel bed

**Given Data:**
- Side slope \( Z \) = 3
- Normal depth \( y \) = 2.87 ft
- Channel bed slope \( S \) = 0.065
- Roughness coefficient \( n \) = 0.013
- Channel base width \( b \) = 4.5 ft

**Steps to Calculate Velocity:**
1. **Calculate the Area (A) of the trapezoidal section:**

\[ A = \left( b + Z \cdot y \right) \cdot y = \left( 4.5 + 3 \cdot 2.87 \right) \cdot 2.87 \]

2. **Calculate the Wetted Perimeter (P):**

\[ P = b + 2 \cdot y \sqrt{1 + Z^2} = 4.5 + 2 \cdot 2.87 \sqrt{1 + 3^2} \]

3. **Calculate the Hydraulic Radius (R):**

\[ R = \frac{A}{P} \]

4. **Apply Manning’s Equation to Find the Velocity (v):**

\[ v = \frac{1}{n} R^{2/3} S^{1/2} \]

By following these steps, you will be able to determine the velocity of the water flow in the trapezoidal channel.
Transcribed Image Text:**Problem Statement:** For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth of 2.87 ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width is 4.5 ft. Calculate the velocity (v) in feet per second (fps). **Explanation:** To solve this problem, you would typically use the Manning's equation for open channel flow, which is given by: \[ v = \frac{1}{n} R^{2/3} S^{1/2} \] where: - \( v \) = velocity (fps) - \( n \) = Manning’s roughness coefficient - \( R \) = hydraulic radius (ft) - \( S \) = slope of the channel bed **Given Data:** - Side slope \( Z \) = 3 - Normal depth \( y \) = 2.87 ft - Channel bed slope \( S \) = 0.065 - Roughness coefficient \( n \) = 0.013 - Channel base width \( b \) = 4.5 ft **Steps to Calculate Velocity:** 1. **Calculate the Area (A) of the trapezoidal section:** \[ A = \left( b + Z \cdot y \right) \cdot y = \left( 4.5 + 3 \cdot 2.87 \right) \cdot 2.87 \] 2. **Calculate the Wetted Perimeter (P):** \[ P = b + 2 \cdot y \sqrt{1 + Z^2} = 4.5 + 2 \cdot 2.87 \sqrt{1 + 3^2} \] 3. **Calculate the Hydraulic Radius (R):** \[ R = \frac{A}{P} \] 4. **Apply Manning’s Equation to Find the Velocity (v):** \[ v = \frac{1}{n} R^{2/3} S^{1/2} \] By following these steps, you will be able to determine the velocity of the water flow in the trapezoidal channel.
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