For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth 2.87 in ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width 4.5. Calculate the velocity (v) in fps.
For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth 2.87 in ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width 4.5. Calculate the velocity (v) in fps.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Problem Statement:**
For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth of 2.87 ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width is 4.5 ft. Calculate the velocity (v) in feet per second (fps).
**Explanation:**
To solve this problem, you would typically use the Manning's equation for open channel flow, which is given by:
\[ v = \frac{1}{n} R^{2/3} S^{1/2} \]
where:
- \( v \) = velocity (fps)
- \( n \) = Manning’s roughness coefficient
- \( R \) = hydraulic radius (ft)
- \( S \) = slope of the channel bed
**Given Data:**
- Side slope \( Z \) = 3
- Normal depth \( y \) = 2.87 ft
- Channel bed slope \( S \) = 0.065
- Roughness coefficient \( n \) = 0.013
- Channel base width \( b \) = 4.5 ft
**Steps to Calculate Velocity:**
1. **Calculate the Area (A) of the trapezoidal section:**
\[ A = \left( b + Z \cdot y \right) \cdot y = \left( 4.5 + 3 \cdot 2.87 \right) \cdot 2.87 \]
2. **Calculate the Wetted Perimeter (P):**
\[ P = b + 2 \cdot y \sqrt{1 + Z^2} = 4.5 + 2 \cdot 2.87 \sqrt{1 + 3^2} \]
3. **Calculate the Hydraulic Radius (R):**
\[ R = \frac{A}{P} \]
4. **Apply Manning’s Equation to Find the Velocity (v):**
\[ v = \frac{1}{n} R^{2/3} S^{1/2} \]
By following these steps, you will be able to determine the velocity of the water flow in the trapezoidal channel.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b7dd8f1-dbab-4607-8b33-bde9974f18c9%2F186268d8-57d6-40e3-affb-549c7c814072%2Fgt3csio_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
For a trapezoidal channel with the horizontal dimension of the side slope is 3 (i.e Z=3), a normal depth of 2.87 ft, and a channel bed slope of 0.065. The channel is lined with concrete with a roughness coefficient of 0.013. The channel base width is 4.5 ft. Calculate the velocity (v) in feet per second (fps).
**Explanation:**
To solve this problem, you would typically use the Manning's equation for open channel flow, which is given by:
\[ v = \frac{1}{n} R^{2/3} S^{1/2} \]
where:
- \( v \) = velocity (fps)
- \( n \) = Manning’s roughness coefficient
- \( R \) = hydraulic radius (ft)
- \( S \) = slope of the channel bed
**Given Data:**
- Side slope \( Z \) = 3
- Normal depth \( y \) = 2.87 ft
- Channel bed slope \( S \) = 0.065
- Roughness coefficient \( n \) = 0.013
- Channel base width \( b \) = 4.5 ft
**Steps to Calculate Velocity:**
1. **Calculate the Area (A) of the trapezoidal section:**
\[ A = \left( b + Z \cdot y \right) \cdot y = \left( 4.5 + 3 \cdot 2.87 \right) \cdot 2.87 \]
2. **Calculate the Wetted Perimeter (P):**
\[ P = b + 2 \cdot y \sqrt{1 + Z^2} = 4.5 + 2 \cdot 2.87 \sqrt{1 + 3^2} \]
3. **Calculate the Hydraulic Radius (R):**
\[ R = \frac{A}{P} \]
4. **Apply Manning’s Equation to Find the Velocity (v):**
\[ v = \frac{1}{n} R^{2/3} S^{1/2} \]
By following these steps, you will be able to determine the velocity of the water flow in the trapezoidal channel.
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