For a thermodynamic system, for process 1: the volume is increased from 0.005 m to 0.015 m under a constant pressure of 250 kPa. After that, the pressure isreduced to 100 kPa under an isochoric process.For the same thermodynamic system, for process 2: with the same starting volume and pressure (i.e. V- 0.005 m and P- 250 kPa), the pressure is reduced to 100kPa under an isochoric process. After that, the volume is increased to 0.015 m under an isobaric processWhat is the difference in work done between process 2 and 1 (ie. Wa Wa7O 20kO 2.5kO-3.0kJ

PROCESS 1 Step 1, Process 1 initial Volume, Vi=0.005 m3 Final volume, Vf=0.015 m3at pressure, Pi=250…

Answered: For a thermodynamic system, for process…

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