For a Student's t distribution with d.f. = 10 and t = 3.080, consider the following. (a) Find an interval containing the corresponding P-value for a two-tailed test. 0.0010 < P-value < 0.0100.010 < P-value < 0.020 0.020 < P-value < 0.0500.050 < P-value < 0.1000.100 < P-value < 0.1500.150 < P-value < 0.2000.200 < P-value < 0.2500.250 < P-value < 0.500 (b) Find an interval containing the corresponding P-value for a right-tailed test. 0.0005 < P-value < 0.0050.005 < P-value < 0.010 0.010 < P-value < 0.0250.025 < P-value < 0.0500.050 < P-value < 0.0750.075 < P-value < 0.1000.100 < P-value < 0.1250.125 < P-value < 0.250

For a Student's t distribution with d.f. = 10 and t = 3.080, consider the following. (a) Find an interval containing the corresponding P-value for a two-tailed test. 0.0010 < P-value < 0.0100.010 < P-value < 0.020 0.020 < P-value < 0.0500.050 < P-value < 0.1000.100 < P-value < 0.1500.150 < P-value < 0.2000.200 < P-value < 0.2500.250 < P-value < 0.500 (b) Find an interval containing the corresponding P-value for a right-tailed test. 0.0005 < P-value < 0.0050.005 < P-value < 0.010 0.010 < P-value < 0.0250.025 < P-value < 0.0500.050 < P-value < 0.0750.075 < P-value < 0.1000.100 < P-value < 0.1250.125 < P-value < 0.250

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

For a Student's t distribution with

d.f. = 10

and

t = 3.080,

consider the following.

(a) Find an interval containing the corresponding P-value for a two-tailed test.

0.0010 < P-value < 0.0100.010 < P-value < 0.020 0.020 < P-value < 0.0500.050 < P-value < 0.1000.100 < P-value < 0.1500.150 < P-value < 0.2000.200 < P-value < 0.2500.250 < P-value < 0.500

(b) Find an interval containing the corresponding P-value for a right-tailed test.

0.0005 < P-value < 0.0050.005 < P-value < 0.010 0.010 < P-value < 0.0250.025 < P-value < 0.0500.050 < P-value < 0.0750.075 < P-value < 0.1000.100 < P-value < 0.1250.125 < P-value < 0.250

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