For a standard normal distribution, find: P(0.8< z < 2.42)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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For a standard normal distribution, find:
P(0.8 < z < 2.42)
Transcribed Image Text:For a standard normal distribution, find: P(0.8 < z < 2.42)
Expert Solution
Step 1

According to given question, 
 
We have:-  
 z1= 0.8  and z2 = 2.42
To find :- 
 P(z1<z<z2) 
Or 
P(0.8<z<2.42
 
Method and formula to find out:-  
P(z1<z<z2)= p(z<z2) -p(z<z1)
So 
 P(0.8<z<2.42)= p(z<2.42)-p(z<0.8) 
first find out Cumulative probabilities from standard normal table for each z score , then we subtract. 
Calculation:- 
 Statistics homework question answer, step 1, image 1
From table 
cumulative  probability can be find out as follows:- 
Row 0.8 column 0.00 we get 0.7881
And Row 2.4 column 0.02 we get 0.9922
It means 
p(z<z2) = p(z<2.42)= 0.9922
p(z<z1)= p(z<0.8) = 0.7881
So
 P(0.8<z<2.42)= p(z<2.42)-p(z<0.8)  
= 0.9922-0.7881
0.2041
Final result:- 
 P(0.8<z<2.42)= 0.2041
 
 
 
 

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