For a standard normal distribution, find: P(0.8< z < 2.42)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Expert Solution
Step 1
According to given question,
We have:-
z1= 0.8 and z2 = 2.42
To find :-
P(z1<z<z2)
Or
P(0.8<z<2.42)
Method and formula to find out:-
P(z1<z<z2)= p(z<z2) -p(z<z1)
So
P(0.8<z<2.42)= p(z<2.42)-p(z<0.8)
first find out Cumulative probabilities from standard normal table for each z score , then we subtract.
Calculation:-
From table
cumulative probability can be find out as follows:-
Row 0.8 column 0.00 we get 0.7881
And Row 2.4 column 0.02 we get 0.9922
It means
p(z<z2) = p(z<2.42)= 0.9922
p(z<z1)= p(z<0.8) = 0.7881
So
P(0.8<z<2.42)= p(z<2.42)-p(z<0.8)
= 0.9922-0.7881
0.2041
Final result:-
P(0.8<z<2.42)= 0.2041
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