For a single sampling plan using MIL-STD, code letter C, normal inspection, and AQL = 25 non-conformities/100 units, the number inspected and the count of non-conformities for the last 10 lots are: Lot number N 555 C 5 5 5 Lot number 6 7 8 9 10 n 1 0 2 1 3 2 4 2 5 1 5 If production is at a steady rate and reduced inspection is authorized, can a change from normal to reduced inspection be initiated? 5555 C 3 1 2 3 1

Q: - 9x + 4 = 49

A: Solving for x

Q: 5+250

A:

Q: 4y-12=0

A: 4y = 12 y = 3

Q: -12 = 4m + 4

A:

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: +100 3

A: Our objective is to find the solution of the above expression.

Q: Divide. y + 10y +21 y +7

A: Dividey2+10y+21y+7

Q: 374+                 =380

A:

Q: 16+29

A: Given :16+29

Q: Vs-+ 12²

A: To determine:

Q: 15+c=-12

A:

Q: 6+197

A: Given,          6+197

Q: t 2X +3 x² イー

A: Simplify the above expression.

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: -16m+8m=340

A:

Q: -3(4x-5)-6=18

A: Given: −34x−5−6=18 To determine: The value of x.