For a second example, consider fk = 3k3 + k – 1. We have Afk = 9k² + 9k + 4, A² fk = 18k + 18, A³ fk = 18, and, from equation (1.189), Cao = -1, a1 = 4, a2 = 9, az = 3. %3D

College Algebra
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ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 44RE: Find the exact solution for 52x3=7x+1. Ifthere isno solution, write no solution.
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For a second example, consider
fk = 3k3 + k – 1.
(1.195)
We have
Afk = 9k2 + 9k + 4, A² fk = 18k + 18, A³ fk = 18,
(1.196)
and, from equation (1.189),
ao = -1,
aj =
4,
2 = 9,
(1.197)
az = 3.
Therefore,
fk = 3k3 + k – 1 = 3k(3)
+ 9k(2)
+ 4k(1)
- 1.
(1.198)
Transcribed Image Text:For a second example, consider fk = 3k3 + k – 1. (1.195) We have Afk = 9k2 + 9k + 4, A² fk = 18k + 18, A³ fk = 18, (1.196) and, from equation (1.189), ao = -1, aj = 4, 2 = 9, (1.197) az = 3. Therefore, fk = 3k3 + k – 1 = 3k(3) + 9k(2) + 4k(1) - 1. (1.198)
that
A™ fo
ат
т %3D 0, 1, ...., п.
(1.189)
m!
To illustrate the use of this theorem, consider the function
fk = k4.
(1.190)
Transcribed Image Text:that A™ fo ат т %3D 0, 1, ...., п. (1.189) m! To illustrate the use of this theorem, consider the function fk = k4. (1.190)
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