For a satellite in an *elliptical* orbit around the earth, the amount of work done in a short time interval by the gravitational force from the earth on the satellite A) is zero B) is positive when the satellite is getting closer to the earth, and negative when it's getting farther from the earth C) is negative when the satellite is getting closer to the earth, and positive when it's getting farther from the earth D) is positive. E) is negative. Hint: Draw a diagram and then use either the work formula or the mechanical energy–the kinetic and gravitational poter nergies–to justify your answer.)
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- 5 of 18 A 4500 kg spacecraft is in a circular orbit 1500 km above the I Review I Constants surface of Mars (mM = 6.42 x 1023 kg, RM = 3.39 x 10 m). Part A How much work must the spacecraft engines perform to move the spacecraft to a circular orbit that is 4500 km above the surface? Express your answer with the appropriate units. HẢ ? w - 1.49 • 1010 J %3D Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback Next > MacBook Air esc 80 DII DD F1 F2 F3 F4 FS F6 F7 FB F9 F10 F11 F12 @ # $ & * 1 2 3 4 7 9. delete Q W E R T Y 一 PThree different objects, all with different masses are initially at rest at the bottom of a set of steps. Each step is of uniform height d. The mass of the object is a multiple of the base mass: m: object one had mass 3.10m, object 2 has mass 1.46m, and object 3 has mass m. Object 3 is on step one, object 2 is on step two, and object one is on step 3. define the total gravitational energy of the three object system to be zero when the objects are at the bottom of the steps. Each answer requires the numerical coefficient to an algebraic expression that uses some combination of variables m, g, and d, where g is the acceleration due to gravity. find a new reference height (measured from the base of the stairs) such that the highest two objects have the exact same gravitational potential energy?Question: Three identical 5.6 kg spheres are located at 3 of the 4 corners (top left, top right, and bottom right) of a square whose sides are 2.8 m in length. How much work must be done on the gravitational field produced by the spheres in order to remove the top right sphere (place it at infinity)? Assume that the 2 spheres that are left behind (top left, bottom right) remain located on opposite corners of the square. A) 1.50 x 10-9 J B) 5.34 x 10-10 J C) 1.89 x 10-10 J D) 2.67 x 10-10 J E) 5.29 x 10-10 J OA E B. C.
- 1. The International Space Station orbits the Earth in an approximately circular orbit at the height of h = 375 km above the Earth's surface. In one complete orbit, is the work done by Earth's gravity on the space station positive, negative, or zero? Draw and Explain.Q19 The concept of escape velocity can be best described as: (A) The initial speed required so that an object will safely orbit the Earth. (B) The speed for an object to be launcned and fly through space forever. (C) The speed necessary for a spacecraft to escape Earth's atmosphere. (D) The velocity needed to provide an initial kinetic energy such that total mechanical energy is zero.An artificial satellite is "parked" in an equatorial circular orbit at an altitude of 103 km above the surface of the Earth. a) What is the speed of the satellite? b) What is the minimum additional velocity that must be imparted to the satellite if it is to escape from Earth's gravitational attraction? G = 6.67 x 10-11*N*m2/kg2 ME = 6.0 x 1024 kg RE = 6.4 x 106 m
- A planet with a radius of 6.00 × 107 m has a gravitational field of magnitude 40.2 m/s2 at the surface. What is the escape speed from the planet? ____km/sPLANETARY MOTION: When the masses of two objects are doubled, which of the following would happen to the gravitational force between the two objects? O Masses of the objects will not affect the gravitational force of the two objects O Masses of the objects will directly affect the gravitational force of the two objects Masses of the objects will inversely affect the gravitational force of the two objects Masses of the objects will either affect or not the gravitational force of the two objects2. For a satellite in a circular orbit around the earth, the gravitational force from the earth on the satellite causes the centripetal acceleration. The amount of work done by the gravitational force from the earth on the satelliteA) is zeroB) is greater than zero.C) is less than zero.D) would be different if the masses of the earth and satellite were different.E) can’t be determined without a calculator and some data.i. Prove your answer by using the formula for work, W: (Hint: Consider just a short segment of the orbit, rather than the full revolution.) ii. Prove your answer by talking about the satellite’s kinetic energy, ∆?� ***also please do it i,ii and write a process detail.
- C7 9.) If the orbit is elliptical, rather than circular, what can be said about the work done by the Sun on Earth? a.) It does not matter whether the orbit is circular or elliptical, no work is done. b.) The work the Sun does on Earth causes the tides. c.) Whether the orbit is circular or elliptical, work must be done to propel Earth around the Sun. d.) If the orbit is elliptical, work is done to speed up or to slow down Earth, depending on its location in orbit. e.) The work the Sun does on Earth accounts for Earth's changes of season.A 1,060 kg meteor strikes the surface of the Moon. What is the work done (in J) on the meteor by the gravitational field of the Moon, if we assume the meteor comes from deep space? The work done by the Moon's gravitational field is equal to the negative of the change of potential energy of the meteor-Moon system. You can assume the meteor comes from infinitely far. What is the final distance of the meteor, if it lands on the Moon's surface? You will need to look up two physical characteristics of the Moon to solve this problem. J5