For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used to find that the value of the linear correlation coefficient is r= 0.833. Using a = 0.05, determine if there is a linear correlation between chest size and weight. What proportion of the variation in weight can be explaine by the linear relationship between weight and chest size? Click here to view a table of critical values for the correlation coefficient. a. Is there a linear correlation between chest size and weight? O A. Yes, because the absolute value of r exceeds the critical value of 0.707. O B. No, because the absolute value of r exceeds the critical value of 0.707. O C. Yes, because r falls between the critical values of - 0.707 and 0.707. O D. The answer cannot be determined from the given information. 6. What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used to find that the value of the linear correlation coefficient is r= 0.833. Using a = 0.05, determine if there is a linear correlation between chest size and weight. What proportion of the variation in weight can be explaine by the linear relationship between weight and chest size? Click here to view a table of critical values for the correlation coefficient. a. Is there a linear correlation between chest size and weight? O A. Yes, because the absolute value of r exceeds the critical value of 0.707. O B. No, because the absolute value of r exceeds the critical value of 0.707. O C. Yes, because r falls between the critical values of - 0.707 and 0.707. O D. The answer cannot be determined from the given information. 6. What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
Minitab was used to find that the value of the linear correlation coefficient is r= 0.833. Using o = 0.05, determine if
there is a linear correlation between chest size and weight. What proportion of the variation in weight can be explained
by the linear relationship between weight and chest size?
Click here to view a table of critical values for the correlation coefficient.
a. Is there a linear correlation between chest size and weight?
A. Yes, because the absolute value of r exceeds the critical value of 0.707.
B. No, because the absolute value of r exceeds the critical value of 0.707.
C. Yes, because r falls between the critical values of - 0.707 and 0.707.
D. The answer cannot be determined from the given information.
b. What proportion of the variation in weight can be explained by the linear relationship between weight and chest
size?
(Round to three decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89d31404-901c-4cb4-8788-ffc7f5a8d5c1%2Ff70affe7-9e18-4acb-8ffd-78f9d4c1293d%2F20vmz94_processed.png&w=3840&q=75)
Transcribed Image Text:For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
Minitab was used to find that the value of the linear correlation coefficient is r= 0.833. Using o = 0.05, determine if
there is a linear correlation between chest size and weight. What proportion of the variation in weight can be explained
by the linear relationship between weight and chest size?
Click here to view a table of critical values for the correlation coefficient.
a. Is there a linear correlation between chest size and weight?
A. Yes, because the absolute value of r exceeds the critical value of 0.707.
B. No, because the absolute value of r exceeds the critical value of 0.707.
C. Yes, because r falls between the critical values of - 0.707 and 0.707.
D. The answer cannot be determined from the given information.
b. What proportion of the variation in weight can be explained by the linear relationship between weight and chest
size?
(Round to three decimal places as needed.)
![Table of Critical Values
4
.950
.990
.878
.959
.811
.917
7
.754
.875
8
.707
.834
9.
.666
.798
10
.632
.765
11
.602
.735
12
.576
.708
13
.553
.684
14
.532
.661
15
.514
.641
16
.497
.623
17
.482
.606
18
.468
.590
19
.456
.575
20
.444
.561
25
.396
.505
30
.361
.463
35
.335
.430
40
.312
.402
45
.294
.378
50
.279
.361
60
.254
.330
70
.236
.305
80
.220
.286
90
.207
.269
100
196
256.
Print
Done](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89d31404-901c-4cb4-8788-ffc7f5a8d5c1%2Ff70affe7-9e18-4acb-8ffd-78f9d4c1293d%2Fiz500ke_processed.png&w=3840&q=75)
Transcribed Image Text:Table of Critical Values
4
.950
.990
.878
.959
.811
.917
7
.754
.875
8
.707
.834
9.
.666
.798
10
.632
.765
11
.602
.735
12
.576
.708
13
.553
.684
14
.532
.661
15
.514
.641
16
.497
.623
17
.482
.606
18
.468
.590
19
.456
.575
20
.444
.561
25
.396
.505
30
.361
.463
35
.335
.430
40
.312
.402
45
.294
.378
50
.279
.361
60
.254
.330
70
.236
.305
80
.220
.286
90
.207
.269
100
196
256.
Print
Done
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