For a refrigerator or air conditioner, the coefficient of performance K (often denoted as COP) is the ratio of cooling output Qc to the required electrical energy input W], both in joules. The coefficient of performance is also expressed as a ratio of powers, K= \Qc\/t \W\/t where Qc\/t is the cooling power and W/t is the electrical power input to the device, both in watts. Y Part A ▾ For a home air conditioner, K is generally determined for a 35°C outside temperature and an 27°C return air temperature. Calculate K for a Carnot device that operates between 35°C and 27°C. K= Submit Part B cost= Submit 195) ΑΣΦ ▾ Part C You have an air conditioner with of 3.2. Your home on average requires a total cooling output of Qc = 2.1 x 10¹0 J per year. If electricity costs you 12.5 pence per kW-h. how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's COP accurately represents the operation of your air conditioner. A seasonal coefficient of performance (SCOP) is often used. The SCOP is calculated over a range of outside temperatures to get a more accurate seasonal average.) Express your answer in pounds. [5] ΑΣΦ 1 → Ć Request Answer savings = Request Answer → C 197| ΑΣΦΑ ? You are considering replacing your air conditioner with a more efficient one with of K = 4.3. Based on the K. how much would that save you on electricity costs in an average year? Express your answer in pounds. → ? GBP ? GBP
For a refrigerator or air conditioner, the coefficient of performance K (often denoted as COP) is the ratio of cooling output Qc to the required electrical energy input W], both in joules. The coefficient of performance is also expressed as a ratio of powers, K= \Qc\/t \W\/t where Qc\/t is the cooling power and W/t is the electrical power input to the device, both in watts. Y Part A ▾ For a home air conditioner, K is generally determined for a 35°C outside temperature and an 27°C return air temperature. Calculate K for a Carnot device that operates between 35°C and 27°C. K= Submit Part B cost= Submit 195) ΑΣΦ ▾ Part C You have an air conditioner with of 3.2. Your home on average requires a total cooling output of Qc = 2.1 x 10¹0 J per year. If electricity costs you 12.5 pence per kW-h. how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's COP accurately represents the operation of your air conditioner. A seasonal coefficient of performance (SCOP) is often used. The SCOP is calculated over a range of outside temperatures to get a more accurate seasonal average.) Express your answer in pounds. [5] ΑΣΦ 1 → Ć Request Answer savings = Request Answer → C 197| ΑΣΦΑ ? You are considering replacing your air conditioner with a more efficient one with of K = 4.3. Based on the K. how much would that save you on electricity costs in an average year? Express your answer in pounds. → ? GBP ? GBP
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![For a refrigerator or air conditioner, the coefficient of performance K
(often denoted as COP) is the ratio of cooling output |Qc to the
required electrical energy input |W, both in joules. The coefficient of
performance is also expressed as a ratio of powers,
K=
Qc\/t
W\/t
where |Qc\/t is the cooling power and W/t is the electrical power
input to the device, both in watts.
Part A
For a home air conditioner, K is generally determined for a 35°C outside temperature and an 27° C return air temperature. Calculate K for a Carnot device that operates
between 35°C and 27° C.
K=
Submit
Part B
cost =
[ΨΕΙ ΑΣΦ
Submit
Part C
You have an air conditioner with of 3.2. Your home on average requires a total cooling output of |QC| = 2.1 x 10¹0 J per year. If electricity costs you 12.5 pence per kW . h.
how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's COP accurately represents the operation of your air conditioner. A
seasonal coefficient of performance (SCOP) is often used. The SCOP is calculated over a range of outside temperatures to get a more accurate seasonal average.)
Express your answer in pounds.
IVE ΑΣΦ
1
savings =
Request Answer
Submit
Request Answer
?
You are considering replacing your air conditioner with a more efficient one with of K = 4.3. Based on the K, how much would that save you on electricity costs in an average
year?
Express your answer in pounds.
V—| ΑΣΦ
Request Answer
?
GBP
?
GBP](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63a56cab-856f-41b5-a5a3-53df189c58ba%2Fec3ebae2-70e1-4b4e-b553-02d42b111701%2Fwx34polb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a refrigerator or air conditioner, the coefficient of performance K
(often denoted as COP) is the ratio of cooling output |Qc to the
required electrical energy input |W, both in joules. The coefficient of
performance is also expressed as a ratio of powers,
K=
Qc\/t
W\/t
where |Qc\/t is the cooling power and W/t is the electrical power
input to the device, both in watts.
Part A
For a home air conditioner, K is generally determined for a 35°C outside temperature and an 27° C return air temperature. Calculate K for a Carnot device that operates
between 35°C and 27° C.
K=
Submit
Part B
cost =
[ΨΕΙ ΑΣΦ
Submit
Part C
You have an air conditioner with of 3.2. Your home on average requires a total cooling output of |QC| = 2.1 x 10¹0 J per year. If electricity costs you 12.5 pence per kW . h.
how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's COP accurately represents the operation of your air conditioner. A
seasonal coefficient of performance (SCOP) is often used. The SCOP is calculated over a range of outside temperatures to get a more accurate seasonal average.)
Express your answer in pounds.
IVE ΑΣΦ
1
savings =
Request Answer
Submit
Request Answer
?
You are considering replacing your air conditioner with a more efficient one with of K = 4.3. Based on the K, how much would that save you on electricity costs in an average
year?
Express your answer in pounds.
V—| ΑΣΦ
Request Answer
?
GBP
?
GBP
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