For a refrigerator or air conditioner, the coefficient of performance K (often denoted as COP) is the ratio of cooling output Qc to the required electrical energy input W], both in joules. The coefficient of performance is also expressed as a ratio of powers, K= \Qc\/t \W\/t where Qc\/t is the cooling power and W/t is the electrical power input to the device, both in watts. Y Part A ▾ For a home air conditioner, K is generally determined for a 35°C outside temperature and an 27°C return air temperature. Calculate K for a Carnot device that operates between 35°C and 27°C. K= Submit Part B cost= Submit 195) ΑΣΦ ▾ Part C You have an air conditioner with of 3.2. Your home on average requires a total cooling output of Qc = 2.1 x 10¹0 J per year. If electricity costs you 12.5 pence per kW-h. how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's COP accurately represents the operation of your air conditioner. A seasonal coefficient of performance (SCOP) is often used. The SCOP is calculated over a range of outside temperatures to get a more accurate seasonal average.) Express your answer in pounds. [5] ΑΣΦ 1 → Ć Request Answer savings = Request Answer → C 197| ΑΣΦΑ ? You are considering replacing your air conditioner with a more efficient one with of K = 4.3. Based on the K. how much would that save you on electricity costs in an average year? Express your answer in pounds. → ? GBP ? GBP
For a refrigerator or air conditioner, the coefficient of performance K (often denoted as COP) is the ratio of cooling output Qc to the required electrical energy input W], both in joules. The coefficient of performance is also expressed as a ratio of powers, K= \Qc\/t \W\/t where Qc\/t is the cooling power and W/t is the electrical power input to the device, both in watts. Y Part A ▾ For a home air conditioner, K is generally determined for a 35°C outside temperature and an 27°C return air temperature. Calculate K for a Carnot device that operates between 35°C and 27°C. K= Submit Part B cost= Submit 195) ΑΣΦ ▾ Part C You have an air conditioner with of 3.2. Your home on average requires a total cooling output of Qc = 2.1 x 10¹0 J per year. If electricity costs you 12.5 pence per kW-h. how much do you spend per year, on average, to operate your air conditioner? (Assume that the unit's COP accurately represents the operation of your air conditioner. A seasonal coefficient of performance (SCOP) is often used. The SCOP is calculated over a range of outside temperatures to get a more accurate seasonal average.) Express your answer in pounds. [5] ΑΣΦ 1 → Ć Request Answer savings = Request Answer → C 197| ΑΣΦΑ ? You are considering replacing your air conditioner with a more efficient one with of K = 4.3. Based on the K. how much would that save you on electricity costs in an average year? Express your answer in pounds. → ? GBP ? GBP
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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