For a reaction under study, a graph of ln k versus 1/T (K−1) was prepared. The line of best fit to the data was determined to be: y = -8.09 × 103x + 31.5 . What is the activation energy, Ea, for this reaction in kJ/mol? A. 31.5 kJ/mol b. 4.79 × 1013 kJ/mol c. 67.3 kJ/mol d. 5.60 × 105 kJ/mol

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For a reaction under study, a graph of ln k versus 1/T (K−1) was prepared. The line of best fit to the data was determined to be: y = -8.09 × 103x + 31.5 . What is the activation energy, Ea, for this reaction in kJ/mol?
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Hint 1. How to determine the activation energyopened hint
The slope of the line is equal to -Ea/R.
 
For a reaction under study, a graph of ln k versus 1/T (K−1) was prepared. The line of best fit to the data was determined to be: y = -8.09 × 103x + 31.5 . What is the activation energy, Ea, for this reaction in kJ/mol?
A. 31.5 kJ/mol
b. 4.79 × 1013 kJ/mol
c. 67.3 kJ/mol
d. 5.60 × 105 kJ/mol
Expert Solution
Step 1

Given : The best fit line for ln(K) v/s 1/T plot is : y = -8.09 * 103 x + 3.15 

 

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