For a random sample of 96 smokers, the mean amount of short-term absenteeism from work was 2.15 hours per month, and the sample standard deviation was 2.09 hours per month. For an independent random sample of 206 employees who had never smoked, the mean amount of absenteeism was 1.69 hours per month, and the sample standard deviation was 1.91 hours per month. Find a 99% confidence interval for the difference between the two population means. O a. -0.19< ux-uy < 111 O b. 0.19 < px-hy <1.11 O ch 0.29< HX-Hy<211 @ d. 0.29< [x-Hy < 2.11 230428145740-46402

MATLAB: An Introduction with Applications
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For a random sample of 96 smokers, the mean amount of short-term absenteeism from work was 2.15 hours per month, and the sample standard deviation was 2.09
hours per month. For an independent random sample of 206 employees who had never smoked, the mean amount of absenteeism was 1.69 hours per month, and the
sample standard deviation was 1.91 hours per month. Find a 99% confidence interval for the difference between the two population means.
O a. -0.19< ux-uy < 111
O b. 019 < px-uy <1.11
O ch 0.29< HX-Hy<211
Q d. 0.29< jx-Hy < 2.11
230428145740-46402
Transcribed Image Text:For a random sample of 96 smokers, the mean amount of short-term absenteeism from work was 2.15 hours per month, and the sample standard deviation was 2.09 hours per month. For an independent random sample of 206 employees who had never smoked, the mean amount of absenteeism was 1.69 hours per month, and the sample standard deviation was 1.91 hours per month. Find a 99% confidence interval for the difference between the two population means. O a. -0.19< ux-uy < 111 O b. 019 < px-uy <1.11 O ch 0.29< HX-Hy<211 Q d. 0.29< jx-Hy < 2.11 230428145740-46402
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