For a population that is left skewed with a mean of 24 and a standard deviation equal to 10, determine the probability of observing a sample mean of 21 or more from a sample of size 31. Click here to view page 1 of the Cumulative Standardized Normal Table. Click here to view page 2 of the Cumulative Standardized Normal Table. What is the probability of observing a sample mean of 21 or more from a sample of size 31? P(x≥21) = (Round to four decimal places as needed.)
For a population that is left skewed with a mean of 24 and a standard deviation equal to 10, determine the probability of observing a sample mean of 21 or more from a sample of size 31. Click here to view page 1 of the Cumulative Standardized Normal Table. Click here to view page 2 of the Cumulative Standardized Normal Table. What is the probability of observing a sample mean of 21 or more from a sample of size 31? P(x≥21) = (Round to four decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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answer the question below
![For a population that is left-skewed with a mean of 24 and a standard deviation equal to 10, determine the probability of observing a sample mean of 21 or more from a sample of size 31.
- [Click here to view page 1 of the Cumulative Standardized Normal Table.](#)
- [Click here to view page 2 of the Cumulative Standardized Normal Table.](#)
---
**What is the probability of observing a sample mean of 21 or more from a sample of size 31?**
\[
P\left(\bar{x} \geq 21\right) = \, \text{[Enter Answer Here]}
\]
*(Round to four decimal places as needed.)*
**Explanation:**
This problem involves calculating the probability of observing a sample mean from a population with a specific distribution. To find this probability, one would typically use the standardized normal (Z) distribution. The links provided offer access to pages of the Cumulative Standardized Normal Table, which is often used to find probabilities associated with the normal distribution.
To solve this problem, you first need to:
1. Calculate the standard error of the mean.
2. Use it to find the Z-score for the sample mean of 21.
3. Use the cumulative standard normal table to find the probability corresponding to this Z-score.
4. Round the answer to four decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff87bdc72-7428-415f-98ff-fbe881a5cc72%2Fc9e0832a-618c-4e4b-8a01-a487f6b5c0f0%2Fz77aw5l_processed.png&w=3840&q=75)
Transcribed Image Text:For a population that is left-skewed with a mean of 24 and a standard deviation equal to 10, determine the probability of observing a sample mean of 21 or more from a sample of size 31.
- [Click here to view page 1 of the Cumulative Standardized Normal Table.](#)
- [Click here to view page 2 of the Cumulative Standardized Normal Table.](#)
---
**What is the probability of observing a sample mean of 21 or more from a sample of size 31?**
\[
P\left(\bar{x} \geq 21\right) = \, \text{[Enter Answer Here]}
\]
*(Round to four decimal places as needed.)*
**Explanation:**
This problem involves calculating the probability of observing a sample mean from a population with a specific distribution. To find this probability, one would typically use the standardized normal (Z) distribution. The links provided offer access to pages of the Cumulative Standardized Normal Table, which is often used to find probabilities associated with the normal distribution.
To solve this problem, you first need to:
1. Calculate the standard error of the mean.
2. Use it to find the Z-score for the sample mean of 21.
3. Use the cumulative standard normal table to find the probability corresponding to this Z-score.
4. Round the answer to four decimal places.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1: Determine the given variables.
The question is about central limit theorem.
Given :
Mean value of the population ( ) = 24
Standard deviation of the population ( ) = 10
No. of observations in the sample ( n ) = 31
To find :
Probability of observing a sample mean 21 or more.
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