p-value: .8980, .5310, .7088, or .9949conclusion: reject the null or fail to reject the null For a one proportion z-test a z-score of 1.27 was calculated. Use the z-chart to determinethe p-value and draw a conclusion about the null hypothesis..0001.02.03.0405.07.08.09.5199.5596.59876368.6736.52395636.60266406 64436772.51205517.5910.6293.666470197357.767379678238.5160.55575948.63316700705473897704.7995.8264.850887295359.5753614165176879.7224.75497852.81338389.8621.88309015917793195279 5319.571461036480.68447190.5080.5478.58710.00.10.20.3.5000539857936179.655469157257.504054385832.6217659169507291.567560646255.6628.6808.715774860.40.50.60.70.80.91.0.69857324.7642.7939.8212.84618686.8888906692227088 7123.74547734 7764 7794.8051.831585548770.896291319279.742275807881.8159.8413751778238106.83657611.80238289.8531.87498944.9115.9265.8078.83408577.87908980.91479292791081868438.8485.8708.8907.9082.9236859988101.11.21.386658869.9049.920786438849.892590999162903291921.492519306p-value:[ Select]Conclusion: [ Select]

Name: p-value: .8980, .5310, .7088, or .9949conclusion: reject the null or f
Uploaded: 2024-03-20T07:07:00.000Z
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Description: p-value: .8980, .5310, .7088, or .9949conclusion: reject the null or fail to reject the null For a one proportion z-test a z-score of 1.27 was calculated. Use the z-chart to determinethe p-value and draw a conclusion about the null hypothesis..0001.0

The p-value is, p-value =p(Z>1.27) =1-p(Z<1.27) =1-0.8980…

Math

Probability

For a one proportion z-test a z-score of 1.27 was calculated. Use the z-chart to determine the p-value and draw a conclusion about the null hypothesis. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .5080 .5000 .5398 .5793 .6179 .5120 .5517 .5910 6293 .5160 .5557 .5948 .5199 .5596 .5239 .5279 .5040 .5438 5832 .5319 5714 .6103 .6480 .6844 7190 0.0 0.1 5359 5753 .5478 .5871 .5675 .6064 .6443 .5636 .6026 .6406 .6772 7123 .7454 .7764 .5987 0.2 0.3 0.4 0.5 0.6 .6217 .6591 .6950 .6141 .6517 .6879 7224 .6331 .6700 6368 .6736 .6255 .6554 .6915 .7257 .6628 .6664 .6808 7157 .6985 .7324 7019 .7357 7673 .7967 7054 7088 7422 .7734 .7486 7549 7852 7291 7389 7517 7794 .7823 .8106 7580 7611 7642 7704 0.7 0.8 .7995 .8264 .8508 8729 .8078 .8340 .7881 .8159 .8413 .8643 .8849 .8133 .8389 .8621 .8830 9015 .9177 .9319 .7910 .8023 .8289 .8051 8315 .7939 .8186 .8438 .8665 .8869 .9049 .8212 .8461 .8686 .8238 .8485 .8708 .8907 .9082 .8365 .8599 .8810 .8997 0.9 .8577 .8531 8749 .8944 .9115 1.0 .8554 .8790 .8980 .9147 .9292 1.1 .8770 .8925 .9099 9251 .8962 .9131 1.2 .8888 9066 .9222 .9162 9306 1.3 .9032 1.4 .9192 .9207 .9236 .9265 9279 p-value: [ Select ] Conclusion: [Select]

For a one proportion z-test a z-score of 1.27 was calculated. Use the z-chart to determine the p-value and draw a conclusion about the null hypothesis. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .5080 .5000 .5398 .5793 .6179 .5120 .5517 .5910 6293 .5160 .5557 .5948 .5199 .5596 .5239 .5279 .5040 .5438 5832 .5319 5714 .6103 .6480 .6844 7190 0.0 0.1 5359 5753 .5478 .5871 .5675 .6064 .6443 .5636 .6026 .6406 .6772 7123 .7454 .7764 .5987 0.2 0.3 0.4 0.5 0.6 .6217 .6591 .6950 .6141 .6517 .6879 7224 .6331 .6700 6368 .6736 .6255 .6554 .6915 .7257 .6628 .6664 .6808 7157 .6985 .7324 7019 .7357 7673 .7967 7054 7088 7422 .7734 .7486 7549 7852 7291 7389 7517 7794 .7823 .8106 7580 7611 7642 7704 0.7 0.8 .7995 .8264 .8508 8729 .8078 .8340 .7881 .8159 .8413 .8643 .8849 .8133 .8389 .8621 .8830 9015 .9177 .9319 .7910 .8023 .8289 .8051 8315 .7939 .8186 .8438 .8665 .8869 .9049 .8212 .8461 .8686 .8238 .8485 .8708 .8907 .9082 .8365 .8599 .8810 .8997 0.9 .8577 .8531 8749 .8944 .9115 1.0 .8554 .8790 .8980 .9147 .9292 1.1 .8770 .8925 .9099 9251 .8962 .9131 1.2 .8888 9066 .9222 .9162 9306 1.3 .9032 1.4 .9192 .9207 .9236 .9265 9279 p-value: [ Select ] Conclusion: [Select]

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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