For a normal variable X~ N(42.3, o = 9.06), find o.16, the value that divides the area under the density curve into 0.84 to the left and 0.16 to the right. (Round the answer to 2 decimal places) 0.16

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A:

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A: Given, n = 25 r = -0.50 SSX = 38 SSY = 14

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Q: None

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A: Required answer