part a, b, c please **Stunt Physics: Jumping Between Rooftops**For a movie stunt, an actor needs to jump from one building's roof to another. The adjacent building's roof is 3 m lower than the roof he is currently on, and there is a 6 m gap between the buildings.### Problem Statement1. **Initial Speed Calculation:** - With what speed does he need to run horizontally off the edge of the roof to just barely land on the other building?2. **Final Speed Before Landing:** - If he runs off the edge with this initial speed, what will be his final speed just before he lands on the other building's roof?3. **Direction of Final Velocity:** - What is the direction of his final velocity (as an angle below the horizontal) just before he lands on the other building's roof?### Analysis1. **Horizontal Speed Calculation:** To ensure the actor lands safely on the lower roof, we need to determine the horizontal speed required. By applying kinematic equations and considering the vertical drop of 3 m and the horizontal distance of 6 m, we can calculate the necessary horizontal speed to just reach the other building.2. **Final Speed Calculation:** By considering the initial horizontal speed and the additional vertical velocity gained due to gravity, we can determine the final speed of the actor just before landing. This involves using the Pythagorean theorem to combine horizontal and vertical components of the velocity.3. **Angle of Final Velocity:** We can find the angle of final velocity below the horizontal by taking the arctangent of the ratio of vertical speed to horizontal speed, providing a clear indication of the direction just before landing.Engage with these calculations to understand the interplay between physics and real-life applications such as stunts in the entertainment industry.

Answered: Image /qna-images/answer/d55fb313-b701-47f6-bc8f-f7f018fc3138.jpg

For a movie stunt, Tom Cruise needs to jump from one building's roof to another. The adjacent building's roof is 3 m lower than the roof he is currently on, and there is a 6 m gap between the buildings. 1. With what speed does he need to run horizontally off the edge of the roof to just barely land on the other building? 2. If he runs off the edge with this initial speed, what will be his final speed just before he lands on the other building's roof? 3. What is the direction of his final velocity (as an angle below the horizontal) just before he lands on the other building's roof?

For a movie stunt, Tom Cruise needs to jump from one building's roof to another. The adjacent building's roof is 3 m lower than the roof he is currently on, and there is a 6 m gap between the buildings. 1. With what speed does he need to run horizontally off the edge of the roof to just barely land on the other building? 2. If he runs off the edge with this initial speed, what will be his final speed just before he lands on the other building's roof? 3. What is the direction of his final velocity (as an angle below the horizontal) just before he lands on the other building's roof?

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: Motion In Two Dimensions

Section: Chapter Questions

Problem 4.3OQ: A student throws a heavy red ball horizontally from a balcony of a tall building with an initial...

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Question

part a, b, c please

**Stunt Physics: Jumping Between Rooftops**

For a movie stunt, an actor needs to jump from one building's roof to another. The adjacent building's roof is 3 m lower than the roof he is currently on, and there is a 6 m gap between the buildings.

### Problem Statement
1. **Initial Speed Calculation:**
- With what speed does he need to run horizontally off the edge of the roof to just barely land on the other building?

2. **Final Speed Before Landing:**
- If he runs off the edge with this initial speed, what will be his final speed just before he lands on the other building's roof?

3. **Direction of Final Velocity:**
- What is the direction of his final velocity (as an angle below the horizontal) just before he lands on the other building's roof?

### Analysis

1. **Horizontal Speed Calculation:**
To ensure the actor lands safely on the lower roof, we need to determine the horizontal speed required. By applying kinematic equations and considering the vertical drop of 3 m and the horizontal distance of 6 m, we can calculate the necessary horizontal speed to just reach the other building.

2. **Final Speed Calculation:**
By considering the initial horizontal speed and the additional vertical velocity gained due to gravity, we can determine the final speed of the actor just before landing. This involves using the Pythagorean theorem to combine horizontal and vertical components of the velocity.

3. **Angle of Final Velocity:**
We can find the angle of final velocity below the horizontal by taking the arctangent of the ratio of vertical speed to horizontal speed, providing a clear indication of the direction just before landing.

Engage with these calculations to understand the interplay between physics and real-life applications such as stunts in the entertainment industry.

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