For a given closed traverse, Lat = -0.44, Dep = -0.37,%3DPerimeter = 2915.80 m%3DTotal Abs dep = 1945.73Total Abs Lat = 1897.4For line AB = 483.52 m, its Latitude is 326.87 N., and dep is 356.30 E. Determine thecorrected departure of AB by compass rule.

To Find :- corrected departure of AB by compass rule. AB length LAB = 483.52 m Perimeter of traverse…

For a given closed traverse, Lat = -0.44, Dep = -0.37, Perimeter = 2915.80 m %3D Total Abs dep = 1945.73 %3D Total Abs Lat = 1897.4 %3D For line AB = 483.52 m. its Latitude is 326.87 N., and dep is 356.30 E. Determine the corrected departure of AB by compass rule.

For a given closed traverse, Lat = -0.44, Dep = -0.37, Perimeter = 2915.80 m %3D Total Abs dep = 1945.73 %3D Total Abs Lat = 1897.4 %3D For line AB = 483.52 m. its Latitude is 326.87 N., and dep is 356.30 E. Determine the corrected departure of AB by compass rule.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Complete solution Topic: : MAGNETIC DECLINATION
The length of a traverse line CD is 316.48m and the magnetic azimuth from south of the line is 153°54'. Determine the departure of CD.
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