For a fixed location, the number of sunlight hours in a day fluctuates throughout the year. Suppose that the number of daily sunlight hours location can be modeled by the following. L)=12+3.1 cos 365 In this equation, L(t) is the number of sunlight hours in a day, and t is the number of days after June 21st, (So t=0 means June 21st,t= 1%3D2 means June 23r4, etc.) Suppose we start at t=0, which is June 2151. During the first 365 days, when will there be 10 hours of sunlight? Do not round any intermediate computations, and round your answer(s) to the nearest day. (If there is more than one answer, enter additi the "or" button.)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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What are the t values? 

For a fixed location, the number of sunlight hours in a day fluctuates throughout the year. Suppose that the number of daily sunlight hours at this location can be modeled by the following:

\[ L(t) = 12 + 3.1 \cos \left( \frac{2 \pi}{365} t \right) \]

In this equation, \( L(t) \) is the number of sunlight hours in a day, and \( t \) is the number of days after June 21st. (So \( t = 0 \) means June 21st, \( t = 2 \) means June 23rd, etc.) Suppose we start at \( t = 0 \), which is June 21st.

**Question:**
During the first 365 days, when will there be 10 hours of sunlight?

*Instructions:*
Do not round any intermediate computations, and round your answer(s) to the nearest day. (If there is more than one answer, enter additional answers using the "or" button.)

**Answer Box:**
\[ t = \boxed{} \text{ days after June 21st} \]
Transcribed Image Text:For a fixed location, the number of sunlight hours in a day fluctuates throughout the year. Suppose that the number of daily sunlight hours at this location can be modeled by the following: \[ L(t) = 12 + 3.1 \cos \left( \frac{2 \pi}{365} t \right) \] In this equation, \( L(t) \) is the number of sunlight hours in a day, and \( t \) is the number of days after June 21st. (So \( t = 0 \) means June 21st, \( t = 2 \) means June 23rd, etc.) Suppose we start at \( t = 0 \), which is June 21st. **Question:** During the first 365 days, when will there be 10 hours of sunlight? *Instructions:* Do not round any intermediate computations, and round your answer(s) to the nearest day. (If there is more than one answer, enter additional answers using the "or" button.) **Answer Box:** \[ t = \boxed{} \text{ days after June 21st} \]
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