For a distribution transformer 20kV:480V, 50HZ, Rated Power 18000 VA working at Power Factor 0.25 The following open circuit test and short circuit test are given as below, Open Circuit Test Results: Measured from secondary side Measured from primary side Voltage: 500 volts Current: 1.4 Amps Short Circuit Test Results: Voltage: 1150 Volts Current: 4 Amps Power: 305 Watts Power: 350 watts Calculate the following Provide your answer to the nearest whole number. Do not use decimal points, text or symbol! Core Resistance (LV side) Rc Ohms Apparent Power S = VA Reactive Power Q = Vars Core Reactance (LV Side) Xm = Ohms Ohms Equivalent Resistance (HV side) Req = Ohms Equivalent impedance (HV side) Zeg = Ohms Equivalent Reactance (HV side) Xeq F Efficiency =

For a distribution transformer 20kV:480V, 50HZ, Rated Power 18000 VA working at Power Factor 0.25 The following open circuit test and short circuit test are given as below, Open Circuit Test Results: Measured from secondary side Measured from primary side Voltage: 500 volts Current: 1.4 Amps Short Circuit Test Results: Voltage: 1150 Volts Current: 4 Amps Power: 305 Watts Power: 350 watts Calculate the following Provide your answer to the nearest whole number. Do not use decimal points, text or symbol! Core Resistance (LV side) Rc Ohms Apparent Power S = VA Reactive Power Q = Vars Core Reactance (LV Side) Xm = Ohms Ohms Equivalent Resistance (HV side) Req = Ohms Equivalent impedance (HV side) Zeg = Ohms Equivalent Reactance (HV side) Xeq F Efficiency =

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A capacitor of capacity C₁ is charged upto V volt and then connected in parallel to an uncharged capacitor of capacity C₂. The final potential difference across each will be (a) (c) C₂V G₁ + C₂ (1+2) GV G + C₂ (4) (1-²) v (b)
10 V sine 90 kHz 1 kQ C1 1 nF 2. Using a Square function with 90,000 Hz in your function-generator, a 1000-ohm resistor, and a 1 nano-Farad capacitor, determine the charging time for the capacitor. Show your calculations and show the charging-discharge curve with an oscilloscope in TINKERCAD.
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1. is the decrease of voltage gain with frequency 2. the capacitance which effectively appears from input to output as the signal is applied is known as
Q2
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