For a distribution function F(x), define F(y) = inf{t: F(t) ≥ y} F (y)inf{t: F(t) > y}. We know F (y) is left-continuous. Show F, (y) is right continuous and show λ{ue (0, 1]: F (u) #F, (u)} = 0, where, as usual, λ is Lebesgue measure. Does it matter which inverse we use?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Question
For a distribution function F(x), define
F(y) = inf{t: F(t) ≥ y}
F(y)inf{t: F(t) > y}.
We know F (y) is left-continuous. Show F, (y) is right continuous and
show
λ{u € (0, 1]: F (u) #F, (u)} = 0,
where, as usual, λ is Lebesgue measure. Does it matter which inverse we
use?
Transcribed Image Text:For a distribution function F(x), define F(y) = inf{t: F(t) ≥ y} F(y)inf{t: F(t) > y}. We know F (y) is left-continuous. Show F, (y) is right continuous and show λ{u € (0, 1]: F (u) #F, (u)} = 0, where, as usual, λ is Lebesgue measure. Does it matter which inverse we use?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer