For a data set obtained from a random sample =R] and --485 It is known that 4s Using 95% confidence level Determine the confidence interval of population mean O a) (3.755 5 845) b) (-0.761,1 329) O)(-0512 1578) d) (47 205 49 295)
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- The test scores on a placement exam are normally distributed random variables with a mean of 104 and standard deviation of 12. 12) Find the probability that a selected test score is less than 117 [[0.8599]] 13) Find the probability that a selected test score is between 92 and 122 [[0.7745]] 14) Find the placement test score that has 75% of the other scores below it. [[104 + 0.67(12) = 112.04]]Below is a 75% confidence interval for a population proportion from a sample of size 90 with sample proportion 59 90 ( 0.598 , 0.713 ) Determine the margin of error for this confidence interval. margin of error = [three decimal accuracy]76026 A) The mean and SD of diameters of a random sample of 9 ball bearings are 2mm and 1.25 mm respectively. The population of diameters of all ball bearings is normally distributed. Obtain the 95% confidence interval for the mean diameter of the population, B) An investigator wants to ascertain the mean time to complete a certain task given to all workers of a plant by taking a raudom sample so that the maximum difference between sample mean and population mean is 2 days with a probability of 0.95 and the standard deviation of the population as 10.5 days. How large should be the size of the sample in this case?
- 7 FI A random sample of ni = 246 people who live in a city were selected and 70 identified as a "dog person." A random sample of n2 Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person.' %3D 112 people who live in a rural area were selected and 62 identified as a "dog person." %3D Round answers to to 4 decimal places. Question Help: Message instructor Submit Question MacBook Pro %23 % 3. 00 R. S. H. K.A random sample of 22 commercials made since the year 2010 have a mean length of 25 seconds with a standard deviation of 14 seconds. The margin of error that corresponds to a 90% confidence interval for the mean length of all commercials made since 2010 is A similar study to the one above was conducted, and the interval was found to be (14.1, 24.1). Can we claim that the mean length of all commercials made since 2010 is more than 15 seconds?A random sample of 240 doctors revealed that 108 are satisfied with the current state of US health care. The conditions for inference are met. Using z* = 1.645, which expression gives a 90% confidence interval for the true proportion of all US doctors who are satisfied with the current state of US health care? 108+1.645 108(1- 108) 240 0.5(1-0.5) 1.645 t108, 240 0.45(1-0.45) 0.45 t1.645, 240 0.5(1-0.5) 0.45 t108 1.645
- 23) The records of 100 postal employees who volunteered for a study, showed that the average time these employees had worked for the postal service was x = standard deviation of the population of time postal service employees have spent with the postal service is approximately 8 years. Assume that we know that the normal with standard deviation o 5 years. A 95% confidence interval for the mean time u the population of postal service employees have spent with the postal service is:The life time (age) in hours of a random sample of one of the batteries produced in Jordan gave the following summary: of Sample size Sample Average Sample Standard deviation n = 9 X = 95 S = 3 A 98% confidence interval for the population standard deviation O is: a) (1.09 , 17.86) b) (1.09 , 6.61) c) (1.89 , 6.61) d) (3.58 , 43.7) e) (1.04, 4.23)Let X1,., X, be iid from Normal(e,0) population (0>0). Use the pivotal quantity to find (1-a) Confidence Interval for 0. ...
- When a population is finite, the formula that determines the standard error of the mean o, needs to be adjusted. If N is the size of the population and n is the size of the N-n . The expression Vn VN-1 N-n is called the finite population correction factor. Use the finite sample (where n20.05N), then the standard error of the mean is o- = N-1 population correction factor to construct the confidence interval for the population mean described below. c =0.99 x=24.4 o = 7.9 N= 800 - n=81 The 99% confidence interval for the population mean is ( ). (Round to two decimal places as needed.)A researcher makes a research about the life time of batteries which have a normal distribution with mean of 50 hours and variance of 9 hours. In order to understand the life time of batteries s/he randomly selected 9 batteries and calculate the sample mean as 48 hours and standard deviation of 5 hours. Construct 80 % confidence interval for the true population mean of life time of batteries. 1- a) (45.43, 50.57) b) (46.04, 49.96) c)O There is no correct answer d) (46.72, 49.28) e) (46.36, 49.65) Boş bırakhis question refers to excavations at a national monument. One question the archaeologists asked was: Is raw material used by prehistoric Indians for stone tool manufacture independent of the archaeological excavation site? Two different excavation sites gave the information in the following table. Use a chi-square test with 5% level of significance to test the claim that raw material used for construction of stone tools and excavation site are independent. Excavation Site Material Site A Site B Row Total Basalt 756 559 1315 Obsidian 92 103 195 Pedernal chert 514 521 1035 Other 88 91 179 Column Total 1450 1274 2724 (a) What is the level of significance? (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)