For a cost of P 100.00, a box of apples was jointly purchased by Maria, Elena and Ana.
For a cost of P 100.00, a box of apples was jointly purchased by Maria, Elena and Ana.
Elementary Algebra
17th Edition
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:Lynn Marecek, MaryAnne Anthony-Smith
Chapter3: Math Models
Section3.3: Solve Mixture Applications
Problem 3.66TI: has $8,000 to save for his daughter’s college education. He wants to divide it between one account...
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How did you derive to get these values (encircled)? Please show the complete solution.
![For a cost of P 100.00, a box of apples was
jointly purchased by Maria, Elena and Ana.
One-half of what Maria paid added to one-
fifth of what Elena paid and one-tenth of what
Ana paid will make it P 40.00, and the sum of
what Maria paid increased by one-eighth of
what Elena paid diminished by 1/4 of what
Ana paid will give a total of P 70.00. How
much did each pay?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fffa4049c-e603-4229-9369-2d09b773cb3d%2Ff4e9d981-440e-49fd-af56-efeb5f18d4fa%2F5xt6vdi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a cost of P 100.00, a box of apples was
jointly purchased by Maria, Elena and Ana.
One-half of what Maria paid added to one-
fifth of what Elena paid and one-tenth of what
Ana paid will make it P 40.00, and the sum of
what Maria paid increased by one-eighth of
what Elena paid diminished by 1/4 of what
Ana paid will give a total of P 70.00. How
much did each pay?
![Let the amount contributed be M, E and A
respectively
M + E + A = 100.........
..i)
0.5M + 0.2E + 0.1A = 40.......ii)
%3D
M+0.125E-0.25A = 70......iii)
.... ... ..
i - 2*ii would lead to - 0.6E + 0.8A = 20
or A = (20 - 0.6E)/0.8.....iv
i- iii -{ 0.875E + 1.25A = 30
%3D
replace A with iv
0.875E + 1.25*(20 - 0.6E)/0.8 = 30
0.7E + 25 - 0.75E = 24
E = 20
put this in iv
A = (20-0.6*20)/0.8 = 10
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fffa4049c-e603-4229-9369-2d09b773cb3d%2Ff4e9d981-440e-49fd-af56-efeb5f18d4fa%2Fi78qwmb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let the amount contributed be M, E and A
respectively
M + E + A = 100.........
..i)
0.5M + 0.2E + 0.1A = 40.......ii)
%3D
M+0.125E-0.25A = 70......iii)
.... ... ..
i - 2*ii would lead to - 0.6E + 0.8A = 20
or A = (20 - 0.6E)/0.8.....iv
i- iii -{ 0.875E + 1.25A = 30
%3D
replace A with iv
0.875E + 1.25*(20 - 0.6E)/0.8 = 30
0.7E + 25 - 0.75E = 24
E = 20
put this in iv
A = (20-0.6*20)/0.8 = 10
%3D
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