For a constant-pressure expansion of a gas, the work done by the system (-w) is equal to the pressure P multiplied by the change in volume (ΔV) of a gas. Calculate the work done by the gas when its volume expands from 3.0 L to 8.0 L under atmospheric pressure. How much heat did it absorb if its energy did not change? Note: 1L atm = 101.325 J

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