For a condensation polymerization between a dibasic acid and a glycol, a material enginee uses 25 moles from each monomer to form polyester and finds that the conversion of reactant is 80%. nHOOC — СH, — СООН + nHО — СН, — НО - CH, - C-0-CH,-0- + 2n H,O C- Use the given information to answer the following: A) What is the polymer molecular weight? B) What is the quantity (moles) of the formed polymer ? C) Prove that M. (repeating unit molecular weight) is the average molecular weight of the structural units where the structural unit is the residue from each monomer.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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For a condensation polymerization between a dibasic acid and a glycol, a material engineer
uses 25 moles from each monomer to form polyester and finds that the conversion of reactants
is 80%.
||
C– CH,–C-0– CH,-O- +2n H,O
||
nHOOC — СH, — СООН + nHO — CН, — НО
-
Use the given information to answer the following:
A) What is the polymer molecular weight?
B) What is the quantity (moles) of the formed polymer ?
C) Prove that M. (repeating unit molecular weight) is the average molecular weight of the
structural units where the structural unit is the residue from each monomer.
Transcribed Image Text:For a condensation polymerization between a dibasic acid and a glycol, a material engineer uses 25 moles from each monomer to form polyester and finds that the conversion of reactants is 80%. || C– CH,–C-0– CH,-O- +2n H,O || nHOOC — СH, — СООН + nHO — CН, — НО - Use the given information to answer the following: A) What is the polymer molecular weight? B) What is the quantity (moles) of the formed polymer ? C) Prove that M. (repeating unit molecular weight) is the average molecular weight of the structural units where the structural unit is the residue from each monomer.
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