For a circular curve of radius 200 m, the coefficient of lateral friction is 0.15 and the design speed is 40 kmph. The equilibrium superelevation would be (а) 21.3 (b) 7 (с) 6.3 (d) 4.6
For a circular curve of radius 200 m, the coefficient of lateral friction is 0.15 and the design speed is 40 kmph. The equilibrium superelevation would be (а) 21.3 (b) 7 (с) 6.3 (d) 4.6
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![For a circular curve of radius 200 m, the
coefficient of lateral friction is 0.15 and the
design speed is 40 kmph. The equilibrium
superelevation would be
(а) 21.3
(b) 7 (с) 6.3
(d) 4.6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1de1c4a2-7330-479d-81b5-ce511e5f748c%2Ff7978025-bb5e-49ba-af37-768fe9372dbd%2Ffz0q55n_processed.png&w=3840&q=75)
Transcribed Image Text:For a circular curve of radius 200 m, the
coefficient of lateral friction is 0.15 and the
design speed is 40 kmph. The equilibrium
superelevation would be
(а) 21.3
(b) 7 (с) 6.3
(d) 4.6
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