For a certain soil, the cohesion is 50 kPa; the unit weight is 19.2 kN/m^3. Assuming local shear failure: (Nc = 7.5, Nq = 1.80, Ny = 0.48) for local shear failure (Nc = 9, Nq = 2.50, Ny = 1.20) for general shear failure. Calculate the net ultimate bearing capacity for a strip footing of width 1.25 m and depth of 4.5 m

For a certain soil, the cohesion is 50 kPa; the unit weight is 19.2 kN/m^3. Assuming local shear failure: (Nc = 7.5, Nq = 1.80, Ny = 0.48) for local shear failure (Nc = 9, Nq = 2.50, Ny = 1.20) for general shear failure. Calculate the net ultimate bearing capacity for a strip footing of width 1.25 m and depth of 4.5 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A circular footing of (225 kPa) is resting on a dry soil with a concentrated load (P) which act at the edge of the footing as shown in figure below. Find the maximum value of P that make the increase in stress at soil element (A) which located 2m under the center of the footing equal to (114 kPa) (use related equations) D=2m N.G.S G=2.62 e=0.43 Soil element A Select one or more: O a. The Concentrated load is about 730 kN
i need the answer quickly
Prob. 3) Referring to the figure below: A) Compute the average increase in stress Ao below the centre of the footing for the clay layer 2. B) Compute the elastic settlement of the clay assuming a shallow foundation. OCR=3, P.I-30%, C-120 kPa, us=0.5. P= 1350 kN G.S. ydry= 17.7 kN/m³ 3 m Clay1 3.mx6 m. 2 m W.T. 2 m ysat= 20 kN/m3 4 m Clay2 ysat= 21 kN/m3 Rigid rock CS Scanned with CamScanner
A square footing 3 m x 3 m is supporting an axial load of 650 kN. The weight of the soil is aasumed to be 17.32 kN/m^3. Compute the vertical stress increment due to this load at a depth of 1.5 m below the center of the footing using the approximate method. a. 51.46 kPa b. 32.10 kPa c. 76.54 kPa d. 50.56 kPa